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postnew [5]
3 years ago
9

What do you know about expressions and equations? What are some examples of expressions and equations? Have you ever thought abo

ut what you should do if you don’t know a certain value? Give an example of how you think you should handle that type of situation.
Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

Answer: An equations is a number, a variable, or a combination of numbers and variables and operational symbols. An equation is made up of two expressions connected by an equal sign.

Example Expression: 8x+5y-3x-5

Example Equation: 5x-4=x

Step-by-step explanation:

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What is the value of y in the equation 2(2y − 12) = 0? <br><br> 4<br><br> 6<br><br> 7<br><br> 8
Elena-2011 [213]
First you distribute making it 4y-24=0
second you isolate the variable making it 4y=24
finally you divide by four giving you the answer of y=6
4 0
3 years ago
Through the point (3,1.2) that has an y intercept of 3
topjm [15]

Answer:

y = -0.6x +3

Step-by-step explanation:

equation of the line through point (3, 1.2) and y-interecept of 3

y= mx+b

m is the slope and b is thhe y-intercept

y = mx + 3

between points (3, 1.2) and (0,3) the slope is

m= (y2-y1)/ (x2-x1) = (1.2-3) / (3-0) = -1.8/3 = -0.6

y = -0.6x +3

3 0
3 years ago
(H/6 )- (1)<br> Solve for H<br> Please help me
likoan [24]

All you need to do for this is remove the parenthese and your answer will be \frac{H}{6} -1 because that's the furthest it can be simplified.

4 0
3 years ago
I need help with 15 mutually exclusive question!!!! Hate stats so much
UNO [17]
Do you have notes that you could share with me? Then maybe I could manage to help out more

8 0
3 years ago
3.The following are real data from Santa Clara County, CA. As of a
zepelin [54]
  • I) the probability that the person is female is 8.33%.
  • II) the probability that the person has a risk factor heterosexual contact is 6.40%.
  • III) the probability that the person is female or has a risk factor of IV drug user is 23.47%.
  • IV) the probability that the person is female and has a risk factor of homosexual is 0%.
  • V) the probability that the person is male and has a risk factor of IV drug user is 15.13%.
  • VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Given the data mentioned in the table, the following calculations must be performed to obtain the requested probabilities:

I.-

(0 + 70 + 136 + 49) / (2,146 + 463 + 60 + 135 + 0 + 70 + 136 + 49) = X

255/3059 = X

0.0833 = X

II.-

196/3059 = X

0.0640 = X

III.-

(255 + 463) / 3059 = X

718/3059 = X

0.2347 = X

IV.-

0/3059 = X

0 = X

V.-

463/3059 = X

0.1513 = X

VI.-

136/196 = X

0.6938 = X

Therefore, I) the probability that the person is female is 8.33%, II) the probability that the person has a risk factor heterosexual contact is 6.40%, III) the probability that the person is female or has a risk factor of IV drug user is 23.47%, IV) the probability that the person is female and has a risk factor of homosexual is 0%, V) the probability that the person is male and has a risk factor of IV drug user is 15.13%, and VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Learn more about maths in brainly.com/question/25815188

3 0
2 years ago
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