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ddd [48]
2 years ago
13

Best answer gets brainiest. On Wednesday at camp, Diana went for a hike at 5:35 A.M. The hike took 1 hour and 30 minutes. As soo

n as she got back from the hike, Diana played volleyball for 55 minutes. What time did Diana finish playing volleyball?
Include A.M. or P.M. in your answer.
Mathematics
2 answers:
andriy [413]2 years ago
6 0

Answer:

She finish playing valleyball at 8:00 am

Step-by-step explanation:

Hike at 5:30 => 1h 30 min => 7:05

valleyball at 7:05 => 55 min => 8:00

MaRussiya [10]2 years ago
4 0

Answer:

Diana finshed playing volleyball at 8am

Step-by-step explanation:

So we know she started at 5:35 AM

And she hiked for an hour and 30 minutes

so 5:35+1 hour is 6:35

and 6:35+35 is 7:05

So before playing volley ball, the time is 7:05 am

Now volley ball was 55 minutes

so 7:05+55 is 8

So 8am

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A company produces x units of a product per month, where c(x) represents the total cost and r(x) represents the total revenue fo
Nat2105 [25]

Answer:

The total profit P(x) or the month is P(x)=-0.5x^2+500x-350.

Step-by-step explanation:

A company produces x units of a product per month.

The total cost represents by the function C(x).

C(x)=300x+250

The total revenue represents by the function R(x).

R(x)=-0.5x^2+800x-100

The profit is the difference between revenue and cost.

P(x)=R(x)-C(x)

P(x)=-0.5x^2+800x-100-(300x+250)

P(x)=-0.5x^2+800x-100-300x-250

Combine like terms.

P(x)=-0.5x^2+(800x-300x)+(-100-250)

P(x)=-0.5x^2+500x-350

Therefore, the total profit P(x) or the month is P(x)=-0.5x^2+500x-350.

5 0
3 years ago
Sam is at the top of a tower and will ride down a zip line to a lower tower. The total vertical drop of the zip line is 40 ft. T
jek_recluse [69]

Answer:

149.30ft

Step-by-step explanation:

Since the vertical distance between the two tower = 40ft

The angle of elevation from the lower tower to te higher tower = 15°

The horizontal distance between the two towers = x

Assuming the angle of elevation and the distance between the two towers makes a right angle triangle, we can use SOHCAHTOA and determine which one would be suitable to find x.

Check attached document for better illustration of the triangle.

Tanθ = opposite / adjacent

Opposite = 40

θ = 15°

Adjacent = x

Tan15 = 40 / x

0.2679 = 40 / x

X = 40 / 0.2679

X = 149.30ft

The horizontal distance between the two towers is 149.30ft

7 0
2 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
1 year ago
22 hours. A
SIZIF [17.4K]

Answer:

100/8 = 12.5 (s)

Step-by-step explanation:

hmm bro

7 0
3 years ago
Read 2 more answers
Determine whether the triangles are similar. or not.
Mashcka [7]

the answer is d not similar

6 0
2 years ago
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