Ball=sphere
Vsphere=pir^3
d/2=r
d=9
9/2=4.5=r
V=pi4.5^3
V=pi91.125
aprox pi=3.141592
V=286.227
round
V=286 in^3
For
|a|>b
assume
a>b and a<-b
|t+4|>10
assume
t+4>10 and t+4<-10
solve each
minus 4 both sides
t>6 and t<-14
A is answer
Answer:
x-intercept(s): (-28, 0)
y-intercept(s): (0, -20)
Step-by-step explanation:
Try This Answer.
25 a² + 20 ab + 4 b²
for formula

find u,v such that: u.v = a
and u+v = b then group according to

=

factor out 5a from :

factor out 2b from :

=

factor out :

=

Refine:

hope this helps!.