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rewona [7]
3 years ago
5

The information given represents lengths of sides of a right triangle with c the hypotenuse. Find the correct missing length to

the nearest hundredth. A calculator may be helpful.
a = ?, b = 11, c = 17

A.
12.96

B.
13.12

C.
13.20

D.
12.75
Mathematics
1 answer:
allochka39001 [22]3 years ago
3 0
The sides of a right triangle can always be expressed as:

h^2=x^2+y^2, where h is the length of the hypotenuse and x and y are the side lengths.

If we are to assume that "a" is a side length then 17 or "c" must be the hypotenuse so:

17^2=11^2+a^2

a^2=289-121

a^2=168

a=√168

a≈12.96  (to nearest hundredth)

Note we knew this assumption because of the answer choices, but technically, "a" COULD have been the hypotenuse without this implicit suggestion making:

a^2=17^2+11^2

a^2=410

a=√410

a≈20.25 (to the nearest hundredth)

Of course the above is not relevant to this particular question but be aware that you won't always be given answer choices to make the assumption of which side is the hypotenuse...


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(4x+4)-(2x-4) would be an equivalent expression.
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Maggie is standing in her front yard and measures the length of the shadow she casts, as well as the shadow, cast by her house.
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Discovery of Trigonometry: #28 What is the length of CA? *
Kamila [148]

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sqrt(3)

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3 years ago
Verify that the points are the vertices of a parallelogram, and find its area. A(1, 1, 3), B(2, −5, 6), C(4, −2, −1), D(3, 4, −4
almond37 [142]

Answer:

Area = 71.3 sq unit

Step-by-step explanation:

a) We will use properties of parallelogram to verify the given vertices.

Property: Have a pair of parallel opposite sides

Hence, vectors AB AD BD BC CD AC. A pair should be parallel:

vectors

AB = A - B = (1, 1 , 3) - ( 2 , -5 , 6 ) = (-1 , 6 , -3)

AD = A - D = (1, 1 , 3) - (3, 4 , -4) = (-2 , -3 , 7)

BC = B - C = (2 , -5 , 6) - (4, -2 , -1) = (-2 ,-3 , 7)

CD = C - D = (4, -2 , -1) - (3, 4 , -4) = (1 , -6 , 3)

Hence we can see  that AB //CD and AD // BC as their unit vector co-efficents are identical/scalar multiple of each other.

b)

Equation of line AB = (1,1,3) + t*(-1 , 6 , -3 )

Point E = (1-t , 1+6t , 3 -3t) ... denotes an position of point E on line AB.

Choose a point on line CD, lets suppose C = ( 4 , -2 , -1 )

Vector EC = ( 1-t , 1+6t , 3-3t ) - (4 , -2 , -1 ) = (-3 -t , 3 +6t , 4 -3t)

For EC to be perpendicular to AB then dot product of AB . EC = 0

Hence,

EC . AB = -1 * (-3-t) -2*(3+6t) -3*(4-3t) = 0

3 + t -6 -12t -12+9t = 0

-2t-3 = 0

t = -3/2

Vector EC = (-3 -t , 3 +6t , 4 -3t) = (-1.5 , -6 , 8.5)

Area = magnitude (AB) * magnitude (EC)

Area = sqrt ((-1)^2 + 6^2 + (-3)^2) * sqrt ((-1.5)^2 + 6^2 + (8.5)^2)

Area = sqrt (46) * sqrt (442) / 2

Area = 71.3 unit^2

6 0
3 years ago
HELP ASAP!!
Grace [21]

Ze Answer to Question:

(In order from most specific to least specific): Integer, Whole number, Counting/Natural Number, Rational Number...

Have a splendid day. My apologies if a sudden mistake is made.

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