The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope
slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5
pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2
y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
y = ( 48 *2 ) / 6
Step-by-step explanation:
If y varies directly as x they are directly proportional, which means they relate to each other in the same way....
2 : y = 6: 48
what is y if x = 2?
The value of y can be found if you write it a two fracrions
2 : y = 6 : 48
2 / y = 6 / 48
cross multiply the fractions gives
6*y = 48 *2
divide left and right of the = sign by 6 gives the answer:
y = ( 48 *2 ) / 6
(if you solve it you get y = 12 but that was not the question).
Other method:
multiply left and right of the = sign by y
2 * y/y = y *6 / 48
6y / 48 = 2 * 1
multiply left and right of the = sign by 48
6y * 48/48 = ( 48 *2 )
6y = ( 48 *2 )
divide left and right of the = sign by 6
6/6* y = ( 48 *2 )/6
y = ( 48 *2 ) / 6
(if you solve it you get y = 12 but that was not the question).
Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.
Step-by-step explanation:
Given function: 
The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.
i.e. 
Hence, f(x) will have vertical asymptotes at x=-2 and x=2.
To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.
So, the graph will horizontal asymptote at 
i.e. 
Hence, f(x) will have horizontal asymptote at y=3.
G(x) is the same as saying y =
y = (2)⁻¹ When an exponent is negative it is the same as the inverse of it
y = 1/2¹
y = 1/2
--or--
g(2) = 1/2
