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Nina [5.8K]
2 years ago
14

Sub to splashy

Computers and Technology
2 answers:
tatyana61 [14]2 years ago
7 0
Ok well make that 19 now
JulsSmile [24]2 years ago
4 0
Ok bet boiiiiiiiiiiiiii
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5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
1. It is a requirement to install a routing protocol that monitors the network for routers that have changed their link state. T
Nady [450]

Answer:

1. Open Shortest Path First (OSPF)

2. Border Gateway Protocol (BGP)

3. Routing and Remote Access Service (RRAS)

4. Frame relay

5. Synchronous

6. Virtual

7. Committed Information Rate (CIR)

8. Integrated Services Digital Network (ISDN)

9. Asynchronous Transfer Mode (ATM)

10. Basic Rate Interface (BRI).

8 0
3 years ago
What is the primary purpose of the software package offered by hyper-v called guest integration services?
zysi [14]

Solution:

Guest integration services resolves compatibility issues of certain guest operating systems experiencing non-functioning features.

Data integration service is the employment of a group of services that comply with service-oriented architecture. Data integration service can perform in an N -> 0 latency time period. At the same time, it offers a powerful set of transformation processes for meeting an array of business imperatives. The advantages of employing data integration as an enterprise service include reduced time for marketing, a reduction in total cost of ownership (TCO), and a solution to the obsolete and expensive data-integration patterns presently available in corporate businesses.

This is the required answer.

6 0
3 years ago
Write a static method that implements a recursive formula for factorials. Place this method in a test program that allows the us
matrenka [14]

Answer:

Written in Java

import java.util.*;

public class Main {

  public static int fact(int n) {

     if (n == 1)

        return n;

     else

        return n * fact(n - 1);

  }

  public static void main(String[] args) {

     int num;

     Scanner input = new Scanner(System.in);

     char tryagain = 'y';

     while(tryagain == 'y'){

     System.out.print("Number: ");

     num = input.nextInt();

     System.out.println(num+"! = "+ fact(num));

     System.out.print("Try another input? y/n : ");

     tryagain = input.next().charAt(0);

}        

  }

}

Explanation:

The static method is defines here

  public static int fact(int n) {

This checks if n is 1. If yes, it returns 1

     if (n == 1)

        return n;

If otherwise, it returns the factorial of n, recursively

     else

        return n * fact(n - 1);

  }

The main method starts here. Where the user can continue executing different values of n. The program keep prompting user to try again for another number until user signals for stoppage

  public static void main(String[] args) {

This declares num as integer

     int num;

     Scanner input = new Scanner(System.in);

This initializes tryagain as y

     char tryagain = 'y';

This checks if user wants to check the factorial of a number

     while(tryagain == 'y'){

This prompts user for input

     System.out.print("Number: ");

This gets user input

     num = input.nextInt();

This passes user input to the function and also prints the result

     System.out.println(num+"! = "+ fact(num));

This prompts user to try again for another value

     System.out.print("Try another input? y/n : ");

This gets user response

     tryagain = input.next().charAt(0);

}        

Download txt
4 0
2 years ago
Using the POP standard for client to server e-mail communication, the e-mail messages remain on the server computer. True False
Gelneren [198K]

Answer:

False

Explanation:

8 0
2 years ago
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