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hoa [83]
3 years ago
8

A student has some​ $1 and​ $5 bills in his wallet. He has a total of 15 bills that are worth ​$35. How many of each type of bil

l does he​ have?
Mathematics
1 answer:
Bumek [7]3 years ago
5 0
He has 5 $5 bills and 10 $1 bills because 5x5=25 and 10x1=10. to check the answer you add 25+10=35.
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The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
$800 at 3.8% interest for 6 months What is the interest? What is the new balance?
ycow [4]

Answer:

  • 800(1+0.038)2

Step-by-step explanation:

800(1+0.038)2

4 0
2 years ago
Read 2 more answers
Can I get the answers for number 14 plz?
nataly862011 [7]
A.
-1: 
2(2)^{-1}  \\ 2( \frac{1}{2}) \\  \frac{2}{2}  \\ 1
(-1,1)

0:
2(2)^{0} \\ 2(1) \\ 2
(0, 2)

1:
2(2)^{1}  \\ 2(2) \\ 4
(1, 4)

2:
2(2)^{2} \\ 2(4) \\ 8
(2, 8)

3:
2(2) ^{3}  \\ 2(8) \\ 16
(3,16)

b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.

Hope this helps!
8 0
3 years ago
Read 2 more answers
Show six <br> ways to add 2,3,4
Gnom [1K]
2 + 3 + 4
2 + 4 + 3
4 + 3 + 2
4 + 2 + 3
3 + 4 + 2
3 + 2 + 4
4 0
3 years ago
Read 2 more answers
1. The three salespeople for a local advertising firm are Sara, Kenny, and Leila. Sara sold $3350 in ads, Kenny sold $1368, and
Dominik [7]

Answer:

\text{Fraction of Sara sold }= \dfrac{1675}{2587}

\text{Fraction of Kenny sold }= \dfrac{684}{2587}

\text{Fraction of Leila sold }= \dfrac{228}{2587}

Step-by-step explanation:

The three salespeople for a local advertising firm are sara, Kenny and Leila.

Sara sold total ads = $3350

Kenny sold total ads = $1368

Leila sold total ads = $456

First we calculate total sale of all three = 3350 + 1368 + 456 = $5174

We need to find fraction of total sale with each person sell.

\text{Fraction of Sara sold }=\dfrac{\text{Sara total sold}}{\text{Total sale by all three}}

\text{Fraction of Sara sold }=\dfrac{3350}{5174}\Rightarrow\dfrac{1675}{2587}\approx 64.75\%

\text{Fraction of Kenny sold }=\dfrac{\text{Kenny total sold}}{\text{Total sale by all three}}

\text{Fraction of Kenny sold }=\dfrac{1368}{5174}\Rightarrow\dfrac{684}{2587}\approx 26.45\%

\text{Fraction of Leila sold }=\dfrac{\text{Leila total sold}}{\text{Total sale by all three}}

\text{Fraction of Leila sold }=\dfrac{456}{5174}\Rightarrow\dfrac{228}{2587}\approx 8.8\%

4 0
3 years ago
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