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3 years ago

U + -5/6 = -1/3 solve for u

Mathematics

2 answers:

Phoenix [80]3 years ago

8 0

Move all terms not containing U to the right side of the equation.

Exact Form:

U = 1/2

Decimal Form:

U = 0.5

stich3 [128]3 years ago

5 0

Answer:U=-7/6

Step-by-step explanation:

U=(-5/6)=-1/3

We want u to stand alone so we bring the - 5/6 to the other side of the equal to sign

So, U=-1/3 +5/6

Then find the lowest common multiple of 3 and 6 and when you find that it will be equal to 6 . Then you ask yourself the denominator which will go into 6 and that number will be multiplied by the numerator

So, U=-2+5/6

U= -7/6

You can cross check if this is correct by adding -7/6 and -5/6

. If you get -1/3 then that is correct

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It takes Lily 10 minutes to walk 1 mile. How many miles can she walk in 1 hour?

netineya [11]

Answer:

she will walk 6 miles in 1 hour! there are 60 minutes in an hour, 60/10=6

3 0

3 years ago

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A 15 foot pole extends t feet below ground and 10 feet above ground. Choose the linear equation that models the situation.

My name is Ann [436]

No options are given for the question :

Answer:

t + 10 = 15

Step-by-step explanation:

Given that :

Length of pole = 15 feet

Height below the ground = t

Height above the ground = 10

Tge linear equation which represents the scenario can be modeled as :

Entire length of pole = 15 feets

Length above ground = 10

Length below ground = t

Length below + length above = total length

t + 10 = 15

8 0

3 years ago

Insert geometric means in each geometric sequence.

Digiron [165]

Answer:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the $n^{th}$ term of a geometric sequence.

$a_n=ar^{n-1}$

Where $a$ is the first term and

$r$ is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

$ar = 24\\ar^4 = \dfrac{3}{64}$

Solving the above equation:

$r = \dfrac{1}{8}$

Therefore, the sequence is:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

Considering the second given sequence:

$ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2$

Therefore, the sequence is:

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

Considering the third sequence:

$a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3$

Therefore, the sequence is:

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

5 0

3 years ago

What is the length of the red vertical edge?<br> Brief explanation please

Ivahew [28]

That's a right triangle

remember, if the legs of a right triangle measure a and b and the hypootnuse is c then a²+b²=c²

so

hypotnuse is longest side, the one oposite the right angle
in this case, it is 5
one leg is 4
and the other one is red, let's call it x

so
x²+4²=5²
x²+16=25
minus 16 both sides
x²=9
sqrt both sides
x=3

the length of the red vertical edge is 3cm

4 0

4 years ago

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Write an equation of the line passing through (-3,4) and (6,5) and give the answer in standard form

Andru [333]

Let's start by putting it into slope-intercept form, which is
y=mx+b where m=slope and b=y-intercept (the value of y when x=0)

Find the slope between (-3, 4) and (6, 5).
Formula for slope: $m=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}$
Plug in our x and y values...
$m=\frac{5-4}{6-(-3)}=\frac{1}9$
Our slope is 1/9.

We can interpret this slope rise/run = 1/9 as
<em>"When y changes by 1, x changes by 9. (and vice versa)"
</em>We want to find the y-intercept. (the value of y when x=0)
Let's take the point (-3, 4).
We want to add 3 to that x to make it 0.
According to our slope, this means adding 1/3 to y. (1 to 9 = 1/3 to 3)
Our y-intercept is at (0, 4 1/3), with the value we use in our eqn. b = 4 1/3.
Let's use an improper fraction, b = 13/3.

Now our equation is $y=\frac{1}9x+\frac{13}3$
Let's convert to standard form, ax+by+c=0.
Just multiply by the LCD of our fractions (in this case, 9)
$9y=x+39$
Now move everything to the left side.
$\boxed{-x+9y-39=0}$

3 0

3 years ago