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WARRIOR [948]
3 years ago
6

Please answer, I’ve been stuck on this the whole day, so basically I only need the four digit code. You can read the instruction

s on the paper. Thank you so much if you decide to answer ❤️.

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0
I got 6103 or BEHI for the answer
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Allison and Rhea got different quotients when they divided 4.80 by 0.12. Whose work is correct? Explain why.
Firlakuza [10]
. 40. If you remove your decimals to do the problem them put it back once you've answered your golden.
6 0
3 years ago
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the number of defectives in 10 different samples of 50 observations each is the following: 5, 1, 1, 2, 3, 3, 1, 4, 2, 3. what is
Law Incorporation [45]

The estimate of the population proportion of defectives is 0.05.

Given that,

There are 10 different samples of 50 observations, that is, total of 500 observations.

To find : The estimate of the population proportion of defectives

And total number of defectives from 500 observations is (5+1+1+2+3+3+1+4+2+3) = 25

Thus, the point estimate for the population proportion defectives will be,

=25/500=0.05

or just obtain the individual proportion of each sample and then take their average to obtain the same result.

Thus, the point estimate for the population proportion defectives will be 0.05

To learn more about proportion click here:

brainly.com/question/2548537

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6 0
1 year ago
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
Please help asap 20 pts
eduard
The discriminant explains how many solutions the quadratic function has. It is found using this formula:

b^2-4ac

Using the formula, there are three rules. Let's say the discriminant=d:
d<0 - No solution ø
d=0 -ONLY 1 solution
d>0 -2 solutions

In the following graph, there are no solutions as the graph does not hit the x-axis at any point. Thereafter, the discriminant MUST be less than zero. Let's view the options check which one agrees with our answer.

A - Discriminant is greater than 0, which means two solutions. This is WRONG.
B - Discriminant is less than 0, which means no solutions. CORRECT!
C- Discriminant is equal to 0, which means one solution. WRONG!

Your answer is B.
7 0
3 years ago
Find it!!!!!!!!!!!!!!​
geniusboy [140]

Answer:

(0,0)

Step-by-step explanation:

If the line is crossing the origin then that means both the x and y intercepts are (0,0)

4 0
3 years ago
Read 2 more answers
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