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3 years ago

13

I'll give brainliest if you give me a good awnser. :)

2 answers:

lbvjy [14]3 years ago

4 0

Answer:

0.5

Explanation:

Paha777 [63]3 years ago

3 0

50x0.01=0.5
The answer is 0.5! I hope this helps you out!!

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A longitudinal wave moves energy that is to the direction of the wave’s movement.

hoa [83]

Answer:

In longitudinal waves, the displacement of the medium is in the same direction as, or the opposite direction to, the direction of propagation of the wave. Mechanical longitudinal waves are also called compressional or compression waves because they produce compression and rarefaction of a medium when traveling through the medium. They are also called pressure waves, because they produce increases and decreases in pressure of the medium. Sound waves is an example of longitudinal wave.

7 0

3 years ago

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Why do you think this is called a high-pressure system? ______________________

madam [21]

Answer:

High in the atmosphere, air pressure decreases. With fewer air molecules above, there is less pressure from the weight of the air above. Places where the air pressure is high, are called high pressure systems. A low pressure system has lower pressure at its center than the areas around it.

Explanation:

Hope this helps you sorry if it doesn’t

8 0

3 years ago

A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.923 g, q = 4.52 µC is locat

Anestetic [448]

Answer:

$Q = -1.43\times 10^[-5} coulomb$

Explanation:

Given data:

particle mass = 0.923 g

particle charge is 4.52 micro C

speed of particle 45.7 m/s

In this particular case, coulomb attraction will cause centrifugal force and taken as +ve and Q is taken as -ve

$-\frac{Qq}{4\pi \epsilon r^2} = \frac{mv^2}{r}$

solving for Q WE GET

$Q = -\frac{mv^2}{r} \times r^2 \frac{4\pi \epsilon}{q}$

$Q = -mv^2\times r \frac{4\pi \epsilon}{q}$

$Q = - \frac{0.923\times 10^{-3} \times 45.7^2\times (22.6\times 10^{-2})} {4.52\times 10^{-6} \times 9\times 10^9}$

where $\frac{1}{4\pi \epsilon} = 9\times 10^9$

$Q = -1.43\times 10^[-5} coulomb$

5 0

4 years ago

lbvjy [14]

Hi there!

1.

The period of a pendulum can be calculated using the following equation:
$\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}$

T = period (s)

L = length of string (m)
g = acceleration due to gravity (m/s²)

Plug in the values:

$T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}$

2.

Calculate the period:

$T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }$

Frequency is the reciprocal of the period, so:

$f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}$

6 0

3 years ago

The lightweight wheel on a road bike has a moment of inertia of 0.097 kg⋅m2. A mechanic, checking the alignment of the wheel, gi

MAVERICK [17]

Answer:

The magnitude of the friction force on the disk is 12.76 N.

Explanation:

Given that,

Moment of inertia = 0.097 kg m²

Number of rotation = 5

Time = 2.4 s

Distance = 7.1 cm

Time = 1.4 s

We need to calculate the angular velocity

Using formula of angular velocity

$\omega=\dfrac{n2\pi}{t}$

Put the value into the formula

$\omega=\dfrac{5\times2\pi}{2.4}$

$\omega=13.08\ rad/s$

We need to calculate the magnitude of the friction force on the disk

Using formula of torque

$\tau=I\alpha$

$F\cdot r=I\alpha$

Put the value into the formula

$F\times7.1\times10^{-2}=0.097\times\dfrac{13.08}{1.4}$

$F\times7.1\times10^{-2}\times1.4=0.097\times13.08$

$F\times0.0994=1.26876$

$F=\dfrac{1.26876}{0.0994}$

$F=12.76\ N$

Hence, The magnitude of the friction force on the disk is 12.76 N.

4 0

3 years ago

Read 2 more answers