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2 answers:
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Answer:
0.9999986*c
Explanation:
The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.
Where
Δt is the travel time as seen by a passenger
Δt' is the travel time as seen by someone on Earth
v is the speed of the ship
c is the speed of light in vacuum
We can replace the fraction v/c with x
It would need to travel at 0.9999986*c
To solve the problem it is necessary to take into account the concepts related to simple pendulum, i.e., a point mass that is suspended from a weightless string. Such a pendulum moves in a harmonic motion -the oscillations repeat regularly, and kineticenergy is transformed into potntial energy and vice versa.
In the given problem half of the period is equivalent to 1 second so the pendulum period is,
From the equations describing the period of a simple pendulum you have to
Where
g= gravity
L = Length
T = Period
Re-arrange to find L we have
Replacing the values,
In the case of the reduction of gravity because the pendulum is in another celestial body, as the moon for example would happen that,
In this way preserving the same length of the rope but decreasing the gravity the Period would increase considerably.
Answer
given,
Area = 0.7 m²
electric field of wave = 0.0400 V/m
time = t =30 s
intensity of electromagnetic wave
c is speed of light
I = 4.24 x 10⁻⁶ W/m²
the amount of energy required
E = I A t
E = 4.24 x 10⁻⁶ x 0.7 x 30
E = 8.9 x 10⁻⁵ J