Question

O

Answer 1

Hi there!

1.

The period of a pendulum can be calculated using the following equation:
$\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}$

T = period (s)

L = length of string (m)
g = acceleration due to gravity (m/s²)

Plug in the values:

$T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}$

2.

Calculate the period:

$T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }$

Frequency is the reciprocal of the period, so:

$f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}$