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ankoles [38]
3 years ago
12

If a solution is forced to dissolve more solute than it normally can dissolve, the solution is

Physics
1 answer:
olganol [36]3 years ago
3 0
A solution is a homogeneous mixture of two or mores substances at molecular level mainly solute and solvents. A solution may be saturated, supersaturated or unsaturated. A saturated solution is when the solution has dissolved the maximum solute at a given temperature, unsaturated solution is a solution which can still dissolve more solute at a given temperature to achieve saturation. In this case, if a solution is forced to dissolve more solute than it normally can dissolve, the solution is supersaturated.
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The current in a toaster is 20 amps, and its voltage is 200 volts. What is the resistance in the toaster?
alukav5142 [94]
<span>Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. 

V = IR
200 = 20R
R = 10 ohms</span>
8 0
2 years ago
Read 2 more answers
What's the time it takes a car to attain the speed of 30 m/s when accelerating from rest at 2 m/s (squared)
bekas [8.4K]
I guess a idk lol good luck tho
6 0
3 years ago
PLEASEEE HELPPPP
solniwko [45]

Answer:

Explanation:

average speed more than 25.0m/s.

5 0
3 years ago
Read 2 more answers
Two electric charges A and B were placed facing each other at a distance of separation "r". The common electrostatic force betwe
lutik1710 [3]

Answer:

From the formula of force:

F =  \frac{kAB}{ {r}^{2} }  \\

since AB and k are constants:

F \:  \alpha  \:  \frac{1}{ {r}^{2} }  \\  \\ F =  \frac{x}{ {r}^{2} }

x is a constant of proportionality

• when force is 4N, separation distance is 1

4 =  \frac{x}{1}  \\ x = 4

therefore, equation becomes

F =  \frac{4}{ {r}^{2} }  \\

when r is doubled, r becomes 2. find F:

F =  \frac{4}{ {2}^{2} }  \\  \\ F =  \frac{4}{4}  \\  \\ { \underline{force \: is \: 1N}}

5 0
3 years ago
Calculate the force generated by a car that hits the wall at an
Makovka662 [10]

This is a defective question. It was WRITTEN by someone who is unclear on the concepts.  DON'T try and answer it.

It's trying to get us to use Newton's second law ... F = m • a.

But that only tells us how much force must act ON THE CAR in order to accelerate it. (45 kg) • (4 m/s^2) = 180 newtons.

This is NOT the force exerted BY the car when it hits something. THAT force depends on its speed WHEN it hits, AND how long it takes for the wreckage to actually come to rest, AND how hard or soft the wall is.

DON'T try to answer this question. Your answer will be wrong, you won't understand why, and the teacher you try to argue with probably won't either.

============================================

More explanation:

Think about jumping off of a ladder in your back yard.  Several times.

Your mass is the same every time.  Your acceleration is the same every time . . . 9.8 m/s² down, the acceleration of Earth gravity, every time.

BUT ...

-- I'll bet you would rather land on wood than on concrete. The force of landing would be less.

-- I'll bet you would rather land on dirt than on wood. The force of landing would be less.

-- I'll bet you would rather land on grass than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a pile of blankets than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a trampoline than on a pile of blankets. The force of landing would be less.

-- I'll bet you would rather jump from a short ladder than from a tall one.  Your speed would be less when you landed, and the force of landing would be less.

==> Your mass is the SAME every time, and your acceleration is the SAME every time.  But the force when you hit is DIFFERENT every time.

The mass and acceleration of the car DON'T tell us the force of the hit when the car hits a wall.  

6 0
3 years ago
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