Explanation:
When we add a non-volatile solute in a solvent then due to the impurity added to the solution there will occur an increase in the boiling point of the solution.
This increase in boiling point will be known as elevation in boiling point.
As one beaker contains seawater (water having NaCl) will have some impurity in it. So, more temperature is required by seawater to escape into the atmosphere.
Whereas another beaker has only pure water so it is able to easily escape into the atmosphere since, it contains no impurity.
Thus, we can conclude that level of pure water will decrease more due to non-volatile solute present in it as compared to seawater.
Answer:
Malachite
Explanation:
Malachite is the only listed compound that must contain copper and oxygen.
Copper and oxygen are both elements found on the periodic table. They have the following symbols;
Copper = Cu
Oxygen = O
From the given choices, only option 1 has the symbol Cu and O.
So only malachite contains both copper and oxygen.
B your welcome no problem no thank you my pleasure
A) Z + 4
In the actual atom, half of the nucleus would be protons and the other half neutrons, hence the 2z. The additional four in the expression must be neutrons because adding protons would change the element all together.
Answer:
sodium sulphide.
Explanation:
First, let us obtain the percentage of sulphur in both compounds. This is illustrated below:
For sodium sulphide(Na₂S):
Molar Mass of Na₂S = (23x2) + 32 = 46 + 32 = 78g/mol
Percentage of sulphur in Na₂S is given by:
32/78 x 100 = 41%
For zinc sulphide(ZnS):
Molar Mass of ZnS = 65.4 + 32 = 97.4g/mol
Percentage of sulphur in ZnS is given by:
32/97.4 x 100 = 33%
From the results obtained sulphur has the highest percentage by mass in sodium sulphide.
