Answer:
K.E = 25 J
Explanation:
Given data:
Mass of ball = 0.5 g
Velocity of ball = 10 m/s
Kinetic energy = ?
Solution:
Formula:
K.E = 1/2 mv²
m = mass
v = velocity
Now we will put the values in formula.
K.E = 1/2 mv²
K.E = 1/2× 0.5kg × (10m/s)²
K.E = 1/2 ×0.5kg × 100m²/s²
K.E = 25 Kg.m²/s²
Kg.m²/s² = J
K.E = 25 J
Answer:
yes
Explanation:
this is because the formula equation shows the details on how they solved the equation
Answer:
We need 7.5 mL of the 1M stock of NaCl
Explanation:
Data given:
Stock = 1M this means 1 mol/ L
A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL
Step 2: Calculate the volume of stock we need
The moles of solute will be constant
and n = M*V
M1*V1 = M2*V2
⇒ with M1 = the initial molair concentration = 1M
⇒ with V1 = the volume we need of the stock
⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L
⇒ with M2 = the concentration of the new solution = 0.15 M
1*V1 = 0.15*(50)
V1 = 7.5 mL
Since 0.0075 L of 1M solution contains 0.0075 moles
50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M
We need 7.5 mL of the 1M stock of NaCl