If we take 2.2 grams of CO2, 6.02 X 1021 atoms of nitrogen and 0.03 gram atoms of sulphur , then the molar ratio of C, N, and O

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3 years ago

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2 answers:

Irina18 [472] · Answer 1 · 2021-11-12T05:41:17+03:00

Answer : The molar ratio of C, N and O are 0.05 : 0.01 : 0.1 or 5 : 1 : 10

Explanation :

First we have to calculate the number of moles $C,N\text{ and }O$ .

(1) 2.2 grams of $CO_2$

First we have to calculate the moles of $CO_2$

$\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=\frac{2.2g}{44g/mole}=0.05moles$

Now we have to calculate the moles of carbon and oxygen.

As, 1 mole of $CO_2$ contains 1 mole of carbon

So, 0.05 mole of $CO_2$ contains 0.05 mole of carbon

The number of moles of carbon (C) = 0.05 mole

As, 1 mole of $CO_2$ contains 2 mole of oxygen

So, 0.05 mole of $CO_2$ contains $2\times 0.05=0.1$ mole of oxygen

The number of moles of oxygen (O) = 0.1 mole

(2) $6.02\times 10^{21}$ atoms of nitrogen.

As, $6.02\times 10^{23}$ atoms of nitrogen present in 1 mole of nitrogen

So, $6.02\times 10^{21}$ atoms of nitrogen present in $\frac{6.02\times 10^{21}}{6.02\times 10^{23}}=0.01$ mole of nitrogen

The number of moles of nitrogen (N) = 0.01 mole

From this we conclude that, the molar ratio of C, N and O are:

C : N : O = 0.05 : 0.01 : 0.1

or,

C : N : O = 5 : 1 : 10

Therefore, the molar ratio of C, N and O are 0.05 : 0.01 : 0.1 or 5 : 1 : 10

Zanzabum · Answer 2 · 2021-11-12T03:37:01+03:00

Answer: -

5 : 1 : 3

Explanation: -

Mass of CO₂ = 2.2 g

Molar mass of CO₂ = 44 g / mol

Number of moles of CO₂ = $\frac{Mass}{Molar mass}$

= $\frac{2.2}{44}$

= 0.05 mol

Number of atoms of nitrogen = 6.02 x 10²¹

Number of moles of nitrogen = $\frac{Number of atoms of nitrogen}{Avogadro's number}$

= $\frac{6.02x1021}{6.02x1023}$

= 0.01 mol

0.03 gram atom of sulphur means 0.03 moles of sulphur.

Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03

= 5 : 1 : 3