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Artist 52 [7]
3 years ago
10

An object has a volume of 220 cm^3 and a mass of 352g. What is the density of the object?

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:

d = m/v

d = 352/220 = 1.6

density is 1.6 g/cm^3

Step-by-step explanation:

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X/10.24=4 tell me what is the answer?
denpristay [2]

Answer:

40.96

Step-by-step explanation:

x/10.24=4

times 10.24 on both sides

10.24 times 4

x=40.96

7 0
3 years ago
Brett painted three walls. Each wall was 9 ft tall and 12 ft long. How much wall area did he paint
julsineya [31]

Answer:

First we need to calculate the are of each wall, since we alredy knew the length (l) and the width (w) which is the height of the wall in this case:

A = wl = 9 . 12 = 108 (ft²)

We also know that he painted 3 walls, we need to multiply our first result by 3, in other words, the area of wall that Brett painted is the sum of the area of three walls: 108 . 3 = 324 (ft²)

8 0
4 years ago
Read 2 more answers
An open box with a square base is to have a volume of 18 ft^3.
kotegsom [21]

Answer:

2.29 ft of side length and 1.14 height

Step-by-step explanation:

a) Volume V = x2h, where x is side of square base and h is hite.

Then surface area S = x2 + 4xh because box is open.

b) From V = x2h = 6 we have h = 6/x2.

Substitude in formula for surface area: S = x2 + 4x·6/x2, S = x2 + 24/x.

We get S as function of one variable x. To get minimum we have to find derivative S' = 2x - 24/x2 = 0, from here 2x3 - 24 = 0, x3 = 12, x = (12)1/3 ≅ 2.29 ft.

Then h = 6/(12)2/3 = (12)1/3/2 ≅ 1.14 ft.

To prove that we have minimum let get second derivative: S'' = 2 + 48/x3, S''(121/3) = 2 + 48/12 = 6 > 0.

And because by second derivative test we have minimum: Smin = (12)2/3 + 4(12)1/3(12)1/3/2 = 3(12)2/3 ≅ 15.72 ft2

5 0
3 years ago
A sprinkler rotates 360 degrees the total are watered is 204yds squared<br> what is the raduius
SIZIF [17.4K]

The radius of the area the sprinkler has watered is 8.06 yards.

<h3>What is Rotation ?</h3>

Rotation is spinning around a fixed point with a fixed radius in circular motions.

It is given that a sprinkler rotates 360 degree

The area watered is 204 sq. yards

Radius = ?

A sprinkler rotates in circle

Therefore the area of the circle = π r²

204 = π r²

204 * 7 /22 = r²

r² = 64.91

r = 8.06 yards

Therefore the radius of the area the sprinkler has watered is 8.06 yards.

To know more about Rotation

brainly.com/question/1571997

#SPJ1

4 0
2 years ago
I need help with Geometry
Bezzdna [24]

Answer:

angle 2 = 120 degrees

angle 3 = 30 degrees

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

4 0
3 years ago
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