All categories

3 years ago

Geometric Series (attached image) muiltx choice WILL GIVE THANKS !!

Mathematics

1 answer:

stepladder [879]3 years ago

7 0

Answer:

Step-by-step explanation:

(B). - 28.7

You might be interested in

A girl has a pen that is a length of 12cm measured to the nearest cm . Her pencil case has a diagonal of length of 12.5cm , meas

velikii [3]

It might not be possible for her to fit her pencil in her pencil case because the pencil might be longer then the pencil case.

6 0

3 years ago

Read 2 more answers

What percent of 82.5 is 21.12?

Lostsunrise [7]

The answer is 0.256..

7 0

3 years ago

Read 2 more answers

A pair of earrings has blue wedges that are all the same size. One earring has a 25 degree yellow wedge. The other has a 14 degr

qwelly [4]

We are given with wedges with angles 25 degrees and 14 degrees. In this case, we can determine the arc length by determining as well the radius of the wedge and converting the degrees of angle to radians. If radius is assumed to be equal, then the wedge with larger angle has a larger arc length

6 0

3 years ago

Read 2 more answers

Rewrite the logarithmic expression as the sum and difference of logarithms. If exponents may be written as the coefficient of a

USPshnik [31]

Answer:

$G(y) = 4\ln(2y+1) - \frac{1}{2}\ln(y^2 + 1)$

Step-by-step explanation:

Given

$G(y) = \ln(\frac{(2y+1)^4}{\sqrt{y^2 + 1}})$

Required

Rewrite as sum and difference

Apply laws of logarithm:

$G(y) = \ln(2y+1)^4 - \ln({\sqrt{y^2 + 1})$

Rewrite the exponents

$G(y) = \ln(2y+1)^4 - \ln(y^2 + 1)^\frac{1}{2}$

Convert exponents to coefficients

$G(y) = 4\ln(2y+1) - \frac{1}{2}\ln(y^2 + 1)$

5 0

4 years ago

Help a brother out lol

Genrish500 [490]

We know that $f(x)=3x+1$ and $g(x)=x^2-6$ ; to find $( \frac{g}{f} )(x)$ we are going to divide $g(x)$ by $f(x)$ :
$( \frac{g}{f} )(x)= \frac{x^2-6}{3x+1}$
Since the denoinatorcan't be zero:
$3x+1 \neq 0$
$x \neq - \frac{1}{3}$

We can conclude that the correct answer is A. $\frac{x^2-6}{3x+1}$ $x \neq - \frac{1}{3}$

3 0

3 years ago