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nignag [31]
3 years ago
9

Jake drew the sketch below of a kite that he wants to make.

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

A. 1/2 (20 x 50) + 1/2 (20 x 10), 2 (1/2 x 20 x 50) + 2(1/2 x 20 x 10)

B. 100

Step-by-step explanation:

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This is the answer
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3 years ago
3x-4 or = to 7<br><br><br> plz help
lisabon 2012 [21]

Answer:

3 + 4 = 7  which is true.

Step-by-step explanation:

Whenever you have an equation with a plain variable (that is, no exponent included), there is only one number that will work when substituted for x.

To solve it, you have to "undo" what is done to the variable. You also go in the reverse order of operations, so you do the addition/subtract first, then multiplication/division.

You also have to do the same to both sides, kind of like keeping a balance scale in balance.

In this case, we subtract 4 from both sides first:

3x + 4 -4 = 7 - 4

The + 4 - 4 cancel each other out, so you get:

3x = 3

3x means "3 times x" so you divide by 3 to undo it. I will use the / to indicate division:

3x / 3 = 3 /3  

so 1x = 1.

Since 1x is "1 times x" it is the same as x by itself, so:

x=1

AND, if we substitute 1 back into the original equation (the asterisk stands for multiply):

3 * 1 + 4 = 7

3 * 1 is 3, so:

3 + 4 = 7     which is true.

1 is the only number that works.

Hope this helped.

3 0
3 years ago
Read 2 more answers
Given m||n, find the value of x. (4x-9)° (3x+29)°​
anzhelika [568]

Answer:

38°

Step-by-step explanation:

4x-9=3x+29 ------- because corresponding angles are equal

x=38°

5 0
3 years ago
Alguien me puede ayudar en este problema plis
Nat2105 [25]

Answer:

3

Step-by-step explanation:

6 0
3 years ago
Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su
Alja [10]

Answer:

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

Step by step explanation:

\frac{ {(4 {n}^{4} {q}^{5})}^{2}  {(8 {n}^{4} q)}^{-2} }{  {(- 3 {nq}^{9})}^{ - 1}   {(4 {n}^{3} {q}^{9})  }^{3} }

first we will change the terms with negative superscrips to the other side of the fraction

\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }

then we will distribute the superscripts

\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2}  {q}^{2} }

\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8}  {q}^{2} }

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

{4}^{2 - 3}  {q}^{10  + 9 - 2 - 27}  {n}^{8 + 1 - 8 - 9}  {8}^{ - 2}  { (- 3)}^{1}

{4}^{ - 1}  {q}^{ - 10}  {n}^{ - 8}  {8}^{ - 2}  { (- 3)}^{1}

then we will change again the terms with negative superscrips to the other side of the fraction

\frac{ - 3}{ 4 \times  {8}^{2}  {q}^{10} {n}^{8}  }

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

4 0
3 years ago
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