The answer is the first one.
Explanation:
X^3 stays the same because there are no other cubed numbers in the problem
Next you combine the x^2s
The x^2s are +3x^2 and +2x^2
Since they are both positive, you add them: 3x^2 + 2x^2 = 5x^2
Next you do the x values
-x and +6x, also known as 6x - x = 5x
Lastly, you just add in the -2 and get:
X^3 + 5x^2 + 5x - 2

8 0

3 years ago

(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde

monitta

Using the distance formula, $d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\$ , what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2 } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2} \\d=\sqrt{36+4} \\d=\sqrt{40} \\$

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

Five or more, let it soar. Four or less, let it rest.

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0

3 years ago