Because $x^2-c=108$ can be rewritten as $x^2-c-108=0$ , finding the value of c so that x=(+-)12 solves this equation it means to find the value of c so that $(+-)12^2-c-108=0$ .
Because $12^2=(-12)^2=144$ , we must find c so that $144-c-108=0$ .
Because $144-108=36$ , c=36.
To check, replace c=36 in the initial equation, and check it is a solution for x=(+-)12.

8 0

3 years ago

What is the polynomial function of least degree whose only zero are -4,2, and 3

lesantik [10]

Answer:

polynomial is one. Because the zeros of a polynomial can be determined from the factors of a polynomial, the factors can be created from the zeros. For the zero which occurs at 2, 3 x x = -2/3, the factor which produced that zero is 2. 3 x §· ¨¸ ©¹ The multiplicity represents how many times that zero occurs, in other words, the degree of ...

Step-by-step explanation:

3 0

3 years ago