How to simplify (-4)(-4)

72 is what percent of 36

Goryan [66]

So the 72 is 200% of 36

8 0

3 years ago

Graph The function f(x) = |2x −4|

Aliun [14]

Answer:this is an absolute value function is there more to the question

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x

Morgarella [4.7K]

Answer:

Foci $(0,\pm\frac{\sqrt{17}}{4})$

Vertices: $(0,\pm 1)$

Eccentricity, e= $\frac{\sqrt{17}}{4}$

Length of latus rectum= $\frac{1}{8}$

Step-by-step explanation:

We are given that

$y^2-16x^2=1$

$y^2-\frac{x^2}{(\frac{1}{4})^2}=1$

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

$y^2/a^2-x^2/b^2=1$ (Along y-axis)

We get

a=1, b=1/4

$a^2+b^2=c^2$

$1+\frac{1}{16}=c^2$

$\frac{16+1}{16}=c^2$

$c^2=\frac{17}{16}$

$c=\pm \frac{\sqrt{17}}{4}$

Therefore,

The coordinates of foci= $(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})$

The coordinated of vertices= $(0,\pm a)=(0,\pm 1)$

Eccentricity, e=c/a

$e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}$

Length of latus rectum= $\frac{2b^2}{a}$

Length of latus rectum= $2\times \frac{1}{16}=\frac{1}{8}$

3 0

3 years ago

Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematic

pishuonlain [190]

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): $\mu \geq 2000$

Alternative hypothesis (H1): $\mu$

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): $\mu \geq 2000$

Alternative hypothesis (H1): $\mu$

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

7 0

3 years ago

The point (4, 10) is in each scatterplot. In which one is it an outlier? On a graph, points (4, 10) and (6, 1) are outside of th

Trava [24]

2,1 I think I hope this helps

5 0

3 years ago