The percentage of data that is roughly greater than 66, as displayed in the box plot, is 100%.
<h3>How to Determine a Percentage of a Data Represented in a Box Plot?</h3>
In a box plot, we have the following displayed five-number summary which tells what percentage of the data distribution for each part of the data distribution:
Upper quartile (Q3): This is the value at where the box in the box plot ends at the edge of the box. From this point to the left, all data values that fall within the bracket make up 75% of the data.
Lower quartile (Q3): This is the value at where the box in the box plot starts at the edge of the box. From this point to the left, all data values that fall within the bracket make up 25% of the data.
Median: this is the middle value at the point where the line divides the box and data below this point make up 50% of the data.
The other five-number summary are the maximum and the minimum values that are represented by the whiskers.
On the box plot given, 66 is at the extreme whisker at the left. This means that the percentage of data that is roughly greater than 66 is 100%.
Learn more about the box plot on:
brainly.com/question/14277132
#SPJ1
Answer:
Step-by-step explanation:
Given that,
The radius of a cylinder, r = 5 cm
Height of the cylinder, h = 5 cm
We need to find the lateral surface area of the cylinder. The formula for the lateral surface area of the cylinder is given by :
Put all the values,
So, the lateral surface area of the cylinder is 
.
The answer is D. 15+18+12+5= 50 and there are 5 ramblers
Top of Statue |
|
|
|
Frank -----------------------------------------------Base
Frank - Base = 400 ft
Base- Top statue = 360 feet
Angle of elevation =Angle Top-Franck-Base, let it be angle Ф
tan (Ф) = 360/400 = 0.9
arc tan (0.9) = tan⁻¹(0.9) = 41.98 ,
Ten angle of elevation Ф ≈ 42°
