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2 years ago

PLS HELP ASAP Solve the equation 1/2x+3/4x=5-2.5x X=_____

Mathematics

2 answers:

777dan777 [17]2 years ago

6 0

I’m pretty sure that X = 4/3

Trava [24]2 years ago

4 0

Answer:

1 1/3

Step-by-step explanation:

x = 4/3 or 1 1/3

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What is 100(0.99988) rounded to the nearest tenth

Deffense [45]

Multiply first then round

3 0

2 years ago

I need to solve this system of equations, how do I do that?<br> 3x-4y=20<br> y=3/4x-5

Paha777 [63]

Answer:

Is is Infinitely many solutions so 0=0

<em><u>Step-by-step explanation:</u></em>

<h3>First we have to rearrange/simplify the equations:</h3>

Equation 1: 4y - 3x = -20

Equation (2): y - 3x/4 = -5

<h3>Then you remove the fractions by multiplication: </h3>

Multiply equation (2) by 4

<h3>The Equations now look like this: </h3>

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

<h3>Solve for y on Equation (2):</h3>

y = <u><em>3x/4 - 5</em></u>

<h3>Then plug in this for the y in Equation 1 and then solve:</h3>

4•(<u><em>3x/4-5</em></u>) - 3x = -20

Therefore the answer leads to:

Infinitely many solutions, 0=0

Hope this helped :')

4 0

2 years ago

Please help!!! Only need help with number 4

Harman [31]

With the symbols given us the symbol for ten and use the symbol for zero 3 times

5 0

3 years ago

Read 2 more answers

① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method

hram777 [196]

Answer:

Step-by-step explanation:

$5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\ S = 9/20\\$

$Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50$

4 0

3 years ago

A lock has a three number code made up of 17 numbers if none of the numbers are allowed to repeat how many different ways can yo

Marrrta [24]

Answer:

680

Step-by-step explanation:

Use the binomial coefficient where you choose $k=3$ numbers out of $n=17$ possible numbers and find the total amount of combinations since order does not matter:

$\displaystyle \binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{17}{3}=\frac{17!}{3!(17-3)!}\\\\\binom{17}{3}=\frac{17!}{3!(14)!}\\\\\binom{17}{3}=\frac{17*16*15}{3*2*1}\\\\\binom{17}{3}=680$

Thus, you can make 680 three-non-repeating-number codes

8 0

1 year ago