Answer: 912
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Work Shown:
The starting term is a1 = 3. The common difference is d = 5 (since we add 5 to each term to get the next term). The nth term formula is
an = a1+d(n-1)
an = 3+5(n-1)
an = 3+5n-5
an = 5n-2
Plug n = 19 into the formula to find the 19th term
an = 5n-2
a19 = 5*19-2
a19 = 95-2
a19 = 93
Add the first and nineteenth terms (a1 = 3 and a19 = 93) to get a1+a19 = 3+93 = 96
Multiply this by n/2 = 19/2 = 9.5 to get the final answer
96*9.5 = 912
I used the formula
Sn = (n/2)*(a1 + an)
where you add the first term (a1) to the nth term (an), then multiply by n/2
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As a check, here are the 19 terms listed out and added up. We get 912 like expected.
3+8+13+18 +23+28+33+38 +43+48+53+58 +63+68+73+78 +83+88+93 = 912
There are 19 values being added up in that equation above. I used spaces to help group the values (groups of four; except the last group which is 3 values) so it's a bit more readable.
Answer:
Step-by-step explanation:
I'm going to guess that the square exponents are on the top y's only? then answer b) looks good
Answer:
Brownies made the most money
Step-by-step explanation:
Let c = cookies
b = brownies
We sold 51 items so c+b = 51
Cookies are .75 and brownies are 1.25
.75c + 1.25 b = 53.25
We have 2 equations and 2 unknowns
c = 51-b
Substituting into the second equation
.75(51-b) + 1.25b = 53.25
Distribute
38.25-.75b +1.25b = 53.25
Combine like terms
38.25+.5b = 53.25
Subtract 38.25 from each side
38.25 +.5b -38.25 = 53.25 -38.25
.5b =15
Divide each side by .5
.5b/.5 = 15/.5
b = 30
Now find c
c =51-b
c = 51-30
c = 21
They sold 30 brownies and 21 cookies
30 brownies * 1.25 =37.50
21 cookies *.75 = 15.75
Brownies made the most money
The answer is in the attachment
Answer:
∠FGI=40°
Step-by-step explanation:
CE║FH ⇒ ∠CDG=∠FGI=40°
