We can use rise over run to determine the slope is 5/8. Using this slope and the point (5,2) we can write the equation: y-2 = 5/8 (x-5)
Decimal form of 5/8 is .625 , so it could be written y-2 = .625*(x-5)
The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
Answer:
B
Step-by-step explanation:
since K is constant ( the same for every point) we can find k when given any point by dividing the y-coordinate by the x-coordinate.
Area=length times width
area=28
length=7
28=7 times width
divide both sides by 7
4=width
the width is 4 miles
and perimiter is 22mi
