Answer:
3 pounds (1.36 kg) of coffee purchased.
Step-by-step explanation:
Since she started with $80 and ended with $58.01 we can find the total amount she spent by subtracting these amounts:
$80 - $58.01 = $21.99
This means that she spent $21.99 on coffee. If each pound cost $7.33, we can divide $21.99 by $7.33 to see how many pounds she bought:
21.99 / 7.33 = 3 pounds (1.36 kg) of coffee purchased.
Hope this helps you!
Have a good evening!
Using a trigonometric identity, the cosine of the angle is given as follows:
![\cos{\theta} = \frac{60}{61}](https://tex.z-dn.net/?f=%5Ccos%7B%5Ctheta%7D%20%3D%20%5Cfrac%7B60%7D%7B61%7D)
<h3>What is the trigonometric identity that relates the sine and the cosine of an angle?</h3>
It is given by:
![\sin^2{\theta} + \cos^2{\theta} = 1](https://tex.z-dn.net/?f=%5Csin%5E2%7B%5Ctheta%7D%20%2B%20%5Ccos%5E2%7B%5Ctheta%7D%20%3D%201)
In this problem, the sine is:
![\sin{\theta} = \frac{11}{61}](https://tex.z-dn.net/?f=%5Csin%7B%5Ctheta%7D%20%3D%20%5Cfrac%7B11%7D%7B61%7D)
Then:
![\cos^2{\theta} = 1 - \sin^2{\theta}](https://tex.z-dn.net/?f=%5Ccos%5E2%7B%5Ctheta%7D%20%3D%201%20-%20%5Csin%5E2%7B%5Ctheta%7D)
![\cos^2{\theta} = 1 - \left(\frac{11}{61}\right)^2](https://tex.z-dn.net/?f=%5Ccos%5E2%7B%5Ctheta%7D%20%3D%201%20-%20%5Cleft%28%5Cfrac%7B11%7D%7B61%7D%5Cright%29%5E2)
![\cos^2{\theta} = \frac{3600}{3721}](https://tex.z-dn.net/?f=%5Ccos%5E2%7B%5Ctheta%7D%20%3D%20%5Cfrac%7B3600%7D%7B3721%7D)
![\cos{\theta} = \pm \sqrt{\frac{3600}{3721}}](https://tex.z-dn.net/?f=%5Ccos%7B%5Ctheta%7D%20%3D%20%5Cpm%20%5Csqrt%7B%5Cfrac%7B3600%7D%7B3721%7D%7D)
On quadrant I, the cosine is positive, hence:
![\cos{\theta} = \frac{60}{61}](https://tex.z-dn.net/?f=%5Ccos%7B%5Ctheta%7D%20%3D%20%5Cfrac%7B60%7D%7B61%7D)
More can be learned about trigonometric identities at brainly.com/question/24496175
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Answer:
hope this helps
Step-by-step explanation:
q =−1/6
Answer and Step-by-step explanation:
The median is the middle of the data set.
Start by crossing off the x's from both sides until you get to the middle.
We get
as the median.
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