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White raven [17]
3 years ago
13

What is 1/3 added to 5/6

Mathematics
2 answers:
Elenna [48]3 years ago
7 0
7/6
Change 1/3 to 2/6 in order to have a common denominator.
Then add the numerators (2 and 5) and keep the denominator. <span />
Alenkinab [10]3 years ago
4 0
The first thing to do is to make the denominators.  Since 3 goes into 6, the first fraction should simply be doubled: 
1/3 + 5/6 = 2/6 + 5/6
5 + 2 = 7
7/6

1/3 + 5/6 = 1 1/6 or 7/6
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Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.  </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.  </em>

<em>The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison? </em>

<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

<em>The comparison would be more accurate using the mean and MAD because the median of both data sets is the same. </em>

<em>The comparison using median and IQR is best because one of the graphs is not symmetrical. </em>

<em>The comparison using median and IQR is best because the median is greater than the IQR for both data sets.</em>

<em />

Mean and MAD are useful for comparison when both data sets are symmetrical.

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4 years ago
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7 0
3 years ago
A contractor needs to fence a rectangular backyard for a client. The length of the backyard should be at least 150 ft, and the d
Butoxors [25]

Answer:

Option: A is correct.

Step-by-step explanation:

Since we are given a information that:

A contractor needs to fence a rectangular backyard for a client.

(1) The length of the backyard should be at least(gretaer than or equal to)            

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     The length of the backyard is denoted by 'y' as in the graph.

  Hence according to statement (1) we have:

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(2) The distance around should be no more than 450 ft.

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So such inequalitiies on graphing will give the graph same as in A option.

Hence option A is correct    


7 0
4 years ago
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