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3 years ago

I need help with this math problem

Mathematics

1 answer:

HACTEHA [7]3 years ago

6 0

Answer:

gfnbxfngm

Step-by-step explanation:

dfdfbsfbxcxx

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6 more then the difference of W and 3

n200080 [17]

Answer:

(w-3) + 6

you have to subtract w and 3 first, then add 6 to it.

3 0

4 years ago

Read 2 more answers

Which set of ordered pairs could be generated by an exponential function?A.(0,0),(1,1),(2,8),(3,27)B.(0,1),(1,2),(2,5),(3,10)C.(

Travka [436]

Answer:

Option D

Step-by-step explanation:

Let an exponential function

$f(x)=ab^x$

Where a=Constant $\neq 0$

$b\neq 0$

We know that

$b^0=1$

Therefore,

Point (0,0) can not be obtained by exponential function.

Hence,option A and C are incorrect.

Substitute (0,1)

$1=a$

$f(x)=b^x$

Substitute (1,2)

$2=b^1$

$\implies b^2=4\neq 5$

Hence, option B is incorrect.

D.(0,1),(1,3),(2,9),(3,27)

$f(1)=b=3$

$b^2=(3)^2=9$

$b^3=3^3=27$

Hence, option D is correct.

4 0

4 years ago

How long must a ladder be to reach the top of 20” wall if the ladder and the wall form a 32 angle at the top

Ann [662]

Answer: 23.58

Step-by-step explanation:

$cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\\cos(32^o)=\dfrac{20}{x}\\\\\\x=\dfrac{20}{cos(32^o)}\\\\\\x=23.58$

7 0

3 years ago

Read 2 more answers

10. Given matrices A, B, and C below, perform the indicated operations if possible. If the operation is not possible, explain wh

Artemon [7]

Answer(a):

Order of matrix A = 3x3 {because number of rows=3, number of columns=3}

Order of matrix B = 3x3

Order of matrix C = 1x3

3A will be of order 3x3 because multiply by scalar doesn't change the order. Which is same as the order of matrix B.

So 3A+B is possible.

We simply multiply all elements of A with 3 and add them with corresponding elements of B.

$3\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}+\begin{bmatrix}5 & 0& 2\\ 1 & -3& 9\\ 2 & 0& 4\end{bmatrix}= \begin{bmatrix}11 & -3& 2\\ 1 & 12& 9.9\\ 5 & 12& 34\end{bmatrix}$

Answer(b):

2B will be of order 3x3 because multiply by scalar doesn't change the order. Which is NOT same as the order of matrix C.

So 2B+C is NOT possible.

Answer(c):

CA is possible only if

number of columns of C = number of columns of A

3=3

which is true hence CA is possible.

$\begin{bmatrix}1 &3 &5 \end{bmatrix}*\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}=\begin{bmatrix}1*2+3*0+5*1 & 1*-1+3*5+5*4 & 1*0+3*0.3+5*10\end{bmatrix}$