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IRISSAK [1]
3 years ago
7

Which set of ordered pairs could be generated by an exponential function?A.(0,0),(1,1),(2,8),(3,27)B.(0,1),(1,2),(2,5),(3,10)C.(

0,0),(1,3),(2,6),(3,9)D.(0,1),(1,3),(2,9),(3,27)
Mathematics
1 answer:
Travka [436]3 years ago
4 0

Answer:

Option  D

Step-by-step explanation:

Let an exponential function

f(x)=ab^x

Where a=Constant\neq 0

b\neq 0

We know that

b^0=1

Therefore,

Point (0,0) can not be obtained by exponential function.

Hence,option A and C are incorrect.

Substitute (0,1)

1=a

f(x)=b^x

Substitute (1,2)

2=b^1

\implies b^2=4\neq 5

Hence, option B is incorrect.

D.(0,1),(1,3),(2,9),(3,27)

f(1)=b=3

b^2=(3)^2=9

b^3=3^3=27

Hence, option D is correct.

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