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2 years ago

4) Maria says you can add any two radicals if you simplify them first. Do you agree with her?

1 answer:

4 0

Answer: Yes, since as we move from left to right in the x axis, the plots in the x axis along with the plots in the y axis also increases.

Step-by-step explanation:

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State the hundred thousands place for 7,832,906,215

juin [17]

Answer:

Step-by-step explanation:

6 is the thousands place

0 (right next to it) is the 10 thousands place

9 is the hundred thousands place. There is only 1 nine present so the answer is unique.

4 0

2 years ago

Which of the following expressions has the greatest value?

Vilka [71]

Answer:

2^5

Step-by-step explanation:

1^10 = 1 (1*1*1*1*1....)

5^2 = 25 (5*5)

2^5 = 32 (2*2*2*2*2)

3^3 = 27 (3*3*3)

5 0

3 years ago

Why does math even exist?

natita [175]

I know I dislike it as well! Sorry you are having trouble with it! :)

4 0

3 years ago

Read 2 more answers

8,minus some number divided by 3, equals 6. find the numbers

algol [13]

8 - (-10) = 18
18 / 3 = 6
hope this helps

5 0

3 years ago

PLEASE HELP MEEEE HURRRY!!! :)

sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

$\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}$

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

$\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}$ First, I swapped the first and third rows.

$\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}$ Leading coefficient of row 2 canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}$ The start value of row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}$ Matrix rows 2 and 3 were swapped.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}$ Leading coefficient in row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}$

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

$\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}$

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0

3 years ago