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Soloha48 [4]
2 years ago
7

4) Maria says you can add any two radicals if you simplify them first. Do you agree with her?

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
4 0

Answer: Yes, since as we move from left to right in the x axis, the plots in the x axis along with the plots in the y axis also increases.

Step-by-step explanation:

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Please help thx a bunch
kirza4 [7]
A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36

B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B


distance between 2 points x and y is |x-y|

so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
4 0
3 years ago
Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou
Anna35 [415]
For this case we have the following equation:
 3 \sqrt{x+6}=-12
 Rewriting we have:
 \sqrt{x+6}= \frac{-12}{3}
 \sqrt{x+6}=-4
 We raise both members of the equation to the square:
 (\sqrt{x+6})^2=(-4)^2
 Rewriting we have:
 x+6=16
 x=16-6
 x=10
 It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
 3 \sqrt{10+6}=-12
 3 \sqrt{16}=-12
 3(4)=-12
 12=-12
 Answer:
 
The solution is:
 
x=10
 It's a extraneous solution

6 0
3 years ago
70 POINTS SIMPLE QUESTION ...im just dumb PLEASE HELP...
gogolik [260]

Answer:

A dilation of 2 about the origin.

Step-by-step explanation:

You can see in the original figure the points are half the points of the transformed figure.

For example the coordinates of H are (0.5,0)

The coordinates of H' are (1,0)

Since 0.5 * 2 = 1

There is a dilation of 2 about the origin.

8 0
3 years ago
Read 2 more answers
Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2
nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0

Now that we've factored our equation, we can use ZPP and break it up:

2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}

So, our solutions are:

x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}

4 0
3 years ago
Please help me , I don’t understand :(
Yuri [45]

Answer:

A. 1.4 times

Step-by-step explanation:

The factor in this exponential function is 1.4.

Please see the attachment.

7 0
3 years ago
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