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It would be 10 hours but the distance would be 260 mph.
Answer:
See explanation
Step-by-step explanation:
Operations Equations Labels
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![\begin{array}{l}\text{Equation 1}\\ \\\text{Equation 2}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%5Ctext%7BEquation%201%7D%5C%5C%20%5C%5C%5Ctext%7BEquation%202%7D%5Cend%7Barray%7D)
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Multiply Equation 1 by -3
New Eq. 1
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Multiply Equation 2 by 5
New Eq. 2
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Add Equations 1 and 2
New Eq. 1
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Divide by 41
y solution
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Substitute y=4 into Equation 2
New Equation 2
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Solve for x
x solution
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Write x and y as coordinates (5,4) Solution to the system
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<span>At the animal shelter there are 56 more dogs than cats. If the total number of animals is 200 how many of each type are in the shelter?
dogs + cats = 200 eq I
</span>dogs = 56 + cats eq II
replace dogs in eq I
(56 + cats) + cats = 200 eq with one variable
56 + 2c = 200
2c = 200 - 56
2c = 144 /divided 2
<u>cats= 72</u>
dogs = 56 + cats = 56 + 72 = 128
<u>dogs = 126</u>
Answer:
a. 60 minutes in one hour.
b. 3,600 seconds in one hour.
c. 1,440 minutes in one day.
d. 86,400 seconds in one day.
e. 10,080 minutes in one week. 604,800 seconds in one week.