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2 years ago

Pls help me I’m new at Geometry :/

Mathematics

2 answers:

prohojiy [21]2 years ago

7 0

Answer:

hope it helps u

Step-by-step explanation:

and pls mark as branlist ans

Delicious77 [7]2 years ago

5 0

Answer:

17.3

Step-by-step explanation:

√(-9-8)² + (-6-(-3))²

√17² + 3²

√289 + 9

√298 = 17.3

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A girl owns 5 pairs of pants, 3 shirts, 2 ties, and 8 jackets. how many different outfits can the girl wear to school if each ou

joja [24]

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5 0

2 years ago

You have an ice cream scoop with a 2-inch diameter. You have an ice cream cone with a 2-inch diameter and a height of 5 inches.

IRISSAK [1]

Answer:

Since the volume of the cone is bigger than the volume of the scoop, it won't spill.

Step-by-step explanation:

In order to calculate if the ice cream will spill we will need to calculate the volume on the ice cream scoop and the volume of the cone. If the volume of the scoop is bigger than the cone it will spill.

volume scoop = (4/3)*pi*r³ = (4/3)*pi*(2/2)³ = 4.1888 in³

volume cone = (pi*r²*h)/3 = [pi*(2/2)²*5]/3 = 5.236 in³

Since the volume of the cone is bigger than the volume of the scoop, it won't spill.

4 0

3 years ago

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

5 0

3 years ago

How do I set this up to solve as a linear equation?

NISA [10]

I don't see any numbers to set up in an equation or letters

4 0

3 years ago

What is a cubic polynomial function in standard form with zeroes 1, –2, and 2?

Lisa [10]

Starting off with the polynomial in standard form would be extremely difficult, but we can construct one fairly easily with the zeroes we've been given.

We know from the given zeroes that our function has the value 0 when x = 1, x = -2, and x = 2. Manipulating each equation, we can rewrite them as x - 1 = 0, x + 2 = 0, and x - 2 = 0. To construct our polynomial, we simply use all three of the expressions on the left side of the equation as factors and multiply them together, obtaining:

$(x-1)(x+2)(x-2)=0$

Notice that we can easily obtain each our three zeroes by dividing both sides by the two other factors. From here, we just need to expand the left-hand side of the equation. I'll show the work required here:

$(x-1)(x+2)(x-2)=0\\
\big[(x-1)x+(x-1)2\big](x-2)=0\\
(x^2-x+2x-2)(x-2)=0\\
(x^2+x-2)(x-2)=0\\
(x^2+x-2)x-(x^2+x-2)2=0\\
x^3+x^2-2x-(2x^2+2x-4)=0\\
x^3+x^2-2x-2x^2-2x+4=0\\
x^3+(x^2-2x^2)+(-2x-2x)+4=0\\
x^3-x^2-4x+4=0\\$

So, in standard form, our cubic polynomial would be $x^3-x^2-4x+4$

3 0

3 years ago