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Triss [41]
3 years ago
9

On a coordinate plane, 2 triangles are shown. Triangle 1 has points at A (negative 3, 4), B (negative 2, 1), C (negative 4, 1).

Triangle 2 has points at A prime (4, negative 2), B prime (3, negative 5), C prime (5, negative 5).
Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?

(x, y) → (x + 7, y + 6)
(x, y) → (x + 7, y – 6)
(x, y) → (x – 6, y + 7)
(x, y) → (x + 6, y + 7)
Mathematics
2 answers:
sergij07 [2.7K]3 years ago
5 0

Answer:

On a coordinate plane, 2 triangles are shown. Triangle F G H has points (1, 1), (4, 5), (5, 1). Triangle F prime G prime H prime has points (negative 1, negative 1), (negative 4, negative 5), (negative 5, negative 1). What are the coordinates of vertex F" of ΔF"G"H"?

Step-by-step explanation:

11Alexandr11 [23.1K]3 years ago
5 0

It's B. (x, y) → (x + 7, y – 6)

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motikmotik

Answer:

We conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.          

Step-by-step explanation:

From the given right-angled triangle,

  • Base = p+1
  • Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

                                            =\frac{1}{2}\left(p+1\right)\left(2p-6\right)

Factor 2p-6: 2(p-3)

                                             =\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}  

Divide the number: 2/2 = 1

                                              =\left(p+1\right)\left(p-3\right)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

                                               =pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)

                                               =pp-3p+1\cdot \:p-1\cdot \:3

                                                =p^2-2p-3

Therefore, we conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.                                        

3 0
3 years ago
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