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Olin [163]
3 years ago
8

Please solve it help me ..............​

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

(a) = iv

b = i

c= ii

d = iii

Q-3

- radical 3

Step-by-step explanation:

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Construc t a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight
GrogVix [38]

The 95% confidence interval for the population standard deviation will be,

$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\

simplifying the equation, we get

$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288

The 95% confidence interval exists (9.887, 21.288).

<h3>What is the  95% of confidence interval?</h3>

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, $n=15, \bar{X}=165.2, s=13.5$

where n exists the sample size, $\bar{X}$ exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be $\alpha=0.05$.

The 95% confidence interval for the population standard deviation will be,

$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\

substitute the values in the above equation, we get

$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\

$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\

simplifying the above equation, we get

$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288

The 95% confidence interval exists (9.887, 21.288).

To learn more about confidence interval refer to:

brainly.com/question/14825274

#SPJ4

6 0
2 years ago
Sam and Maria were shopping for school supplies. Each purchased different quantities of the same notebook and thumb drive. Sam b
salantis [7]

Answer:

idk

Step-by-step explanation:

idkkkkkkkkkkkkkk

6 0
4 years ago
In how many ways can 4 people have different birth months?
Agata [3.3K]

Answer:

48

12 (the number of months in a year) multiplied by 4 (the number of people)

6 0
3 years ago
Explain why the mass of an object remains the same both on earth and on the moon, but the same cannot be said about the weight o
Troyanec [42]

Answer.                        Mass is a measurement of how much matter is in an object; weight is a measurement of how hard gravity is pulling on that object. Your mass is the same wherever you are, on Earth; on the moon; floating in space, because the amount of stuff you're made of doesn't change.  hope this help.............

6 0
3 years ago
Xian and his cousin kai both collect stamps. Xian has 52 stamps, and kai has 76 stamps. The boys recently joined different stamp
Darya [45]

<em><u>Explanation</u></em>

Xian has 52 stamps and Kai has 76 stamps.

Xian's club will send him 16 new stamps per month and Kai's club will send him 12 new stamps per month.

Suppose, Xian and Kai will have the same number of stamps after x months.

So, the total number of new stamps for Xian = 16x and the total number of new stamps for Kai = 12x

So, the equation will be......

52+16x=76+12x\\ \\ 16x-12x=76-52\\ \\ 4x= 24\\ \\ x=6

Thus, Xian and Kai will have the same number of stamps after 6 months.

The number of stamps for each of them will be: 52+16(6)=148

8 0
3 years ago
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