Answer:The set fee would be $15
Explanation:The set fee is the starting value. This means that it is the value of the y at x = 0 (y-intercept).
To get the set fee, we would first need to get the equation of the line.
Equation of the linear line has the following general formula:
y = mx + c
where m is the slope and c is the y-intercept
1- getting the slope:we are given two points which are:
(20,25) and (50,40)
the slope =

The equation now is:
y = 0.5x + c
2- getting the value of the y-intercept:To get the value of the c, we will use any of the given points, substitute in the equation and solve for c.
I will choose the point (20,25)
y = 0.5x + c
25 = 0.5(20) + c
25 = 10 + c
c = 15
The equation of the line representing the scenario is:y = 0.5x + 15
Now, we know that the value of the c is the y-intercept which is the initial value of the function at x=0.
In our situation, this represents the set fee.
Hope this helps :)
The correct answer is: [D]: " 7.2 units" .
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Explanation:
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Use the Pythagorean theorem:
a² + b² = c² ;
in which: "6 units" and "4 units" equal the lengths of the right angle (formed by the rectangle); and "c" is the length of the diagonal of the rectangle, or the "hypotenuse", of the right triangle formed by the rectangle; We wish to solve for "c" ;
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6² + 4² = c² ; Solve for "c" ;
↔ c² = 6² + 4² ;
= (6*6) + (4*4) ;
= 36 + 16 ;
= 52 ;
c² = 52 ;
Take the "positive square root" of each side of the equation; to isolate "c" on one side of the equation; and to solve for "c" ;
√(c²) = √52 ;
c = √52 ;
At this point, we know the 7² = 49 ; 8² = 64 ; so, the answer is somewhere between "7" and "8" ; yet closer to "7" ; so among the answer choices given;
The correct answer is: [D]: " 7.2 units" .
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However, let use a calculator:
c = √52 = 7.2111025509279786 ; which rounds to "7.2" ;
which corresponds to:
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Answer choice: [C]: " 7.2 units" .
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Answer:
Step-by-step explanation:
- Amount = £2500
- Interest rate = 15%
<u>Interest </u>
I do not have an answer for that, but you should try looking for that on google or yahoo answers.