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lisov135 [29]
3 years ago
11

The midpoint of line segment AB is (-2,1). If the coordinates of B are (0,2) what are the coordinates of A?

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

The required coordinate of A will be at (-4, 0)

When a point bisects a line, it cuts the line into two equal parts and the point on that line is known as its midpoint. The expression for calculating the midpoint of a line is expressed as;

M(X, Y)= [{ \frac{x_2+x_1}{2} , \frac{y_2+y_1}{2} ] where:

X =\frac{x_2+x_1}{2} \\Y=\frac{y_2+y_1}{2}

From the question, we are given the following coordinate points

X=-2\\x_1=0\\

Get x₂;

X =\frac{x_2+x_1}{2}\\-2 =\frac{x_2+0}{2}\\2 \times -2=x_2+0\\-4=x_2\\ Swap\\x_2=-4\\

Get y₂;

Y =\frac{y_2+y_1}{2}\\1 =\frac{y_2+2}{2}\\2 \times 1=y_2+2\\2=y_2+2\\y_2=2-2\\y_2=0

Hence the coordinate of A will be (-4, 0)

Learn more about the midpoint here: brainly.com/question/18315903

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For the particular solution, consider the ansatz x_p=a_0, whose first and second derivatives vanish. Substitute x_p and its derivatives into the equation:

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and with x'(0)=-19,

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17 4
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Our final answer is 34 days.
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