Answer: There are 12 white and blue cars more than silver and red cars
Number of white cars: n1=25
Number of blue cars: n2=17
Number of white and blue cars: n3=n1+n2=25+17→n3=42
Number of silver cars: n4=21
Number of red cars: n5=9
Number of silver and red cars: n6=n4+n5=21+9→n6=30
How many more white and blue cars are there than silver and red cars?
n=?
n=n3-n6=42-30→n=12
Answer: There are 12 white and blue cars more than silver and red cars.
Answer:
26.28 m
Step-by-step explanation:
the whole explanation along with solution has been found in attachment. Please go through it.
Answer:
m<1 = 150°
Step-by-step explanation:
Given:
m<1 = (4x + 50)°
m<2 = (7x - 25)°
Required:
m<1
Solution:
To find m<1, we need to create an equation that will enable us determine the value of x.
Thus,
4x + 50 = 7x - 25 => corresponding angles are congruent to each other
4x + 50 - 7x = 7x - 25 - 7x (subtraction property of equality)
-3x + 50 = - 25
-3x + 50 - 50 = -25 - 50 (substraction property of equality)
-3x = -75
-3x/-3 = -75/-3 (division property of equality)
x = 25
✅m<1 = (4x + 50)°
Plug in the value of x
m<1 = 4*25 + 50 = 100 + 50
m<1 = 150°
Answer:
⏃ rational number can be expressed as ⏃ number that can be written in the form of ⏃ fracton.
