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3 years ago

It's due in like 10 minutes please help me out

Mathematics

1 answer:

Naily [24]3 years ago

7 0

Answer:

it should be x=4

Step-by-step explanation:

The line that is perpendicular to

−

is a horizontal line, because horizontal and vertical lines (

- and

- axes for example) are perpendicular. Therefore, this line will take the form

where

is the

-coordinate of the point passed through. The

-coordinate of the given ordered pair

(

−

)

, so the equation must be

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The sum of 12 and twice Chrissy's savings

Mrrafil [7]

24 should be your answer

8 0

3 years ago

At a baseball game , jose bought five hot dogs and three sodas for $17. At the same time, Allision bought two hot dogs and four

OLga [1]

Let d = cost of hotdog
Let s = cost of soda
5d + 3s = 17
2d + 4s = 11 Answer: d = $2.50
s = $1.50
Check:5(2.5) + 3(1.5)=17
12.5 + 4.5 = 17
17 = 172(2.5) + 4(1.5) = 11
5 + 6 = 11
11 = 11 I have done this problem befoore and this is how i work it out

3 0

3 years ago

Calculus 2 master needed; evaluate the integral PLEASE SHOW STEPS IF IM WRONG <img src="https://tex.z-dn.net/?f=%5Cint%7Bsin%5E3

sweet [91]

Answer:

Yes, you answer is correct! It just needs to be simplified :)

Step-by-step explanation:

So we have the integral:

$\int \frac{\sin^3(x)}{\sqrt{\cos(x)}}dx$

As you had done, we can split off the numerator:

$=\int \frac{\sin(x)(\sin^2(x))}{\sqrt{\cos(x)}}dx$

Using the Pythagorean Identity, this is:

$=\int \frac{\sin(x)(1-\cos^2(x))}{\sqrt{\cos(x)}}dx$

Now, we can do u-substitution. Let u equal cos(x). Thus:

$u=\cos(x)\\du=-\sin(x)dx\\-du=\sin(x)dx$

So:

$=\int \frac{1-u^2}{\sqrt{u}}(-du)$

Simplify:

$=-\int\frac{1-u^2}{\sqrt u}du$

We can then split the terms:

$=-\int \frac{1}{\sqrt u}-\frac{u^2}{\sqrt u}du$

Expand the integral:

$=-(\int \frac{1}{\sqrt u}du-\int\frac{u^2}{\sqrt u}du)$

Simplify each of the u.

For the left, that is simply u^-1/2.

For the right, it is u^(2-1/2) or u^3/2. Thus:

$=-(\int u^{-\frac{1}{2}}du-\int u^{\frac{3}{2}}du)$

Reverse Power Rule:

$=-(\frac{u^{1+-\frac{1}{2}}}{1+-\frac{1}{2}}-\frac{u^{1+\frac{3}{2}}}{1+\frac{3}{2}})$

Simplify:

$=-(\frac{u^{\frac{1}{2}}}{\frac{1}{2}}-\frac{u^{\frac{5}{2}}}{\frac{5}{2}})$

Simplify further:

$=-(2u^{\frac{1}{2}}-\frac{2u^{\frac{5}{2}}}{5})$

Distribute the negative:

$=-2u^{\frac{1}{2}}+\frac{2u^{\frac{5}{2}}}{5}$

And substitute back cos(x) for u:

$=-2\cos^{\frac{1}{2}}(x)+\frac{2\cos^{\frac{5}{2}}(x)}{5}$

And this is precisely what you got, so well done!

We can simplify this by first multiplying the first term by 5 to get a common denominator. So:

$=-\frac{10\cos^{\frac{1}{2}}(x)}{5}+\frac{2\cos^{\frac{5}{2}}(x)}{5}$

Combine:

$=\frac{-10\cos^{\frac{1}{2}}(x)+2\cos^{\frac{5}{2}}(x)}{5}$

Factor out a cos^(1/2)(x) and a 2. Since we factored out a cos^(1/2)(x), we need to subtract their exponents inside. Thus:

$=\frac{2\cos^{\frac{1}{2}}(x)(-5\cos^{\frac{1}{2}-\frac{1}{2}}(x)+\cos^{\frac{5}{2}-\frac{1}{2}}(x))}{5}$

Simplify:

$=\frac{2\cos^{\frac{1}{2}}(x)(-5+\cos^2(x))}{5}$

Simplify:

$=\frac{2\sqrt{\cos{x}}(\cos^2(x)-5)}{5}$

And, of course, C:

$=\frac{2\sqrt{\cos{x}}(\cos^2(x)-5)}{5}+C$

So:

$\int \frac{\sin^3(x)}{\sqrt{\cos(x)}}dx=\frac{2\sqrt{\cos{x}}(\cos^2(x)-5)}{5}+C$

And we're done :)

3 0

3 years ago

Read 2 more answers

Anwser fast please help me

victus00 [196]

Step-by-step explanation:

3/4 kg + 2/5 kg

= 0.75 + 0.4

= 1.15kg in total

6 0

3 years ago

In the data set shown, calculate the Mean and median absolute deviation 0,2,4,6, 8,12,8,4

Alexandra [31]

Answer:

the mean is 44 but i don't know the MAD

Step-by-step explanation:

To find the mean absolute deviation of the data, start by finding the mean of the data set.

0 , 2 , 4 , 4 , 6 , 8 , 8 , 12
The mean is 44

The only thing i could tell you is the mean

7 0

3 years ago