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GrogVix [38]
3 years ago
9

PLS HELPPPPP DUE TODAYYYY

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

1. y=4x

2. y=-7x-8

3. y=5x+63

4. y=¾x+8

5. y=-3x-½

6. y=1x-3

7. y=2

8. y=-2x+1

9. y=4x+7

wor<u>k for 9</u>

1=4(2)+b

1= 8 +b

-8 -8

7=b

10. y=0

11. y=¾x+6

<u>work </u><u>for </u><u>1</u><u>1</u>

<em>9</em><em> </em><em>=¾(4)+b</em>

<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>

<em>+b-3=-3</em>

<em>+b-3=-3 6=</em><em>b</em>

<em>1</em><em>2</em><em>.</em><em> </em><em>sorry </em><em>I </em><em>haven't</em><em> </em><em>done </em><em>thai </em><em>one </em><em>in </em><em>a </em><em>while.</em>

<em>I </em><em>was </em><em>too </em><em>lazy </em><em>to </em><em>include</em><em> </em><em>the </em><em>work </em><em>for </em><em>the </em><em>first </em><em>couple</em><em> </em><em>of </em><em>answers</em><em> </em><em>although</em><em> </em><em>I </em><em>recommend</em><em>.</em><em> </em>

<em>M</em>

<em>A</em>

<em>T</em>

<em>H</em>

<em>W</em>

<em>A</em>

<em>Y</em>

<em>they </em><em>include</em><em> </em><em>work </em><em>with </em><em>ads</em>

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At 10:57 A.M. A submarine was at a depth of feet. Its depth then changed at a rate of -8 feet per minute. What was its depth at
Tatiana [17]

Answer:

<h3>48 feet</h3>

Step-by-step explanation:

First we need to get the total minutes used by the submarine from  10:57 A.M to  11:03 A.M. The total minutes used within the specified period of time is 6 minutes.

If its depth then changed at a rate of 8 feet per minute, the submarine depth after 6 minutes will be expressed as shown;

8 feet = 1minute

x feet = 6 minutes

cross multiply;

x * 1 = 8 * 6

x = 48 feet

Hence the submarine depth at 11.03AM is 48 feet

4 0
3 years ago
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Does this have a total amount to it?
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6. Can an isosceles triangle be an obtuse triangle? Explain.
kondor19780726 [428]

Answer:

No. It can be obtuse angle are angles greater than 90° but less than 180°

And for an isosceles triangle, two angles must be equal so if two angles are greater than 90° that mean the sum of angle in a triangle is above 180° which is not possible

Step-by-step explanation:

5 0
2 years ago
The lateral surface area of cone A is equal to the lateral surface area of cylinder B.
Natasha2012 [34]

Answer:

TRUE

Step-by-step explanation:

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Clearly, both the lateral areas are equal

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ZanzabumX [31]
The first thing you should know are properties of exponents to solve the problem.
 For this case the radical form is given by the writing of the expression in the form of root.
 We have then:
 t^-3/4 =4^root(t^-3)=4^root ((1)/(t^3))
answer  t^-3/4=4^root((1)/(t^3))
5 0
3 years ago
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