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GrogVix [38]
3 years ago
9

PLS HELPPPPP DUE TODAYYYY

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

1. y=4x

2. y=-7x-8

3. y=5x+63

4. y=¾x+8

5. y=-3x-½

6. y=1x-3

7. y=2

8. y=-2x+1

9. y=4x+7

wor<u>k for 9</u>

1=4(2)+b

1= 8 +b

-8 -8

7=b

10. y=0

11. y=¾x+6

<u>work </u><u>for </u><u>1</u><u>1</u>

<em>9</em><em> </em><em>=¾(4)+b</em>

<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>

<em>+b-3=-3</em>

<em>+b-3=-3 6=</em><em>b</em>

<em>1</em><em>2</em><em>.</em><em> </em><em>sorry </em><em>I </em><em>haven't</em><em> </em><em>done </em><em>thai </em><em>one </em><em>in </em><em>a </em><em>while.</em>

<em>I </em><em>was </em><em>too </em><em>lazy </em><em>to </em><em>include</em><em> </em><em>the </em><em>work </em><em>for </em><em>the </em><em>first </em><em>couple</em><em> </em><em>of </em><em>answers</em><em> </em><em>although</em><em> </em><em>I </em><em>recommend</em><em>.</em><em> </em>

<em>M</em>

<em>A</em>

<em>T</em>

<em>H</em>

<em>W</em>

<em>A</em>

<em>Y</em>

<em>they </em><em>include</em><em> </em><em>work </em><em>with </em><em>ads</em>

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a box contains red markers, blue markers, and green markers there are more blue markers than red markers. the probability of ran
Natali [406]

Answer:

there isn't enough information but the chance to get red is lower than 20%

Step-by-step explanation:

6 0
4 years ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
3 years ago
The length of a rectangle is three times its width. if the area of the rectangle is 300 yd2 , find its perimeter.
Svetradugi [14.3K]
Let, width = x
Length = 3x

It is given that, 3x * x = 300
3x² = 300
x² = 300 / 3
x = √100
x = 10
& 3x = 3(10) = 30

Perimeter = 2(l + w)
P = 2(10 + 30)
P = 2(40) = 80

In short, Your Answer would be 80 Yards

Hope this helps!
4 0
3 years ago
Consider the sequence: 10,6,2,-2,-6, . . . . <br><br> a)graph the first five terms of the sequence
kotykmax [81]

Answer:

-6, -2, 2, 6, 10

Step-by-step explanation:

8 0
3 years ago
Are the length of a side of a square and the area of the square related proportionally? Why or why not?
Sliva [168]

Answer:

Yes, the length of a side of a square and the perimeter of the square are related proportionally.

Step-by-step explanation:

4 0
3 years ago
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