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3 years ago

9

PLS HELPPPPP DUE TODAYYYY

1 answer:

Dafna1 [17]3 years ago

6 0

1. y=4x

2. y=-7x-8

3. y=5x+63

4. y=¾x+8

5. y=-3x-½

6. y=1x-3

7. y=2

8. y=-2x+1

9. y=4x+7

wor<u>k for 9</u>

1=4(2)+b

1= 8 +b

-8 -8

7=b

10. y=0

11. y=¾x+6

<u>work </u><u>for </u><u>1</u><u>1</u>

<em>9</em><em> </em><em>=¾(4)+b</em>

<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>

<em>+b-3=-3</em>

<em>+b-3=-3 6=</em><em>b</em>

<em>1</em><em>2</em><em>.</em><em> </em><em>sorry </em><em>I </em><em>haven't</em><em> </em><em>done </em><em>thai </em><em>one </em><em>in </em><em>a </em><em>while.</em>

<em>I </em><em>was </em><em>too </em><em>lazy </em><em>to </em><em>include</em><em> </em><em>the </em><em>work </em><em>for </em><em>the </em><em>first </em><em>couple</em><em> </em><em>of </em><em>answers</em><em> </em><em>although</em><em> </em><em>I </em><em>recommend</em><em>.</em><em> </em>

<em>M</em>

<em>A</em>

<em>T</em>

<em>H</em>

<em>W</em>

<em>A</em>

<em>Y</em>

<em>they </em><em>include</em><em> </em><em>work </em><em>with </em><em>ads</em>

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Will mark brainliest if right!!!!!!

77julia77 [94]

Answer:

sorry if wrong put b as the answer

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3 years ago

HELPPPPPP MEEEEE<br><br> y=6x-1<br><br> and -2x-3y=-2 <br><br><br> USING SUBSTITUTION

bazaltina [42]

Answer:
x = 4
y =23

work:
plug in the value of Y to -2x-3y=-2. -2x - 3(<span>6x-1) = -2
multiply 3 and the numbers in parenthesis. -2x -18x - 3 =-2
combine like terms (-2x -18x). -20x - 3 = -2
subtract 3 from both sides to isolate the variable. -20x = -5
divide to isolate the variable (-20/-5) x = 4
-
now that we know the value of x, it'll be easy to find Y.
Plug it in to the first equation.
</span><span>y=6(4)-1
</span>y = 24 - 1
y = 23

so x = 4
and y = 23

hope this helps! :D

7 0

4 years ago

-x + y = 4<br>x + 3y =4

Ymorist [56]

The answer is -2,2 for this problem

3 0

3 years ago

ITS TIMED PLEASE HELP

Lubov Fominskaja [6]

Answer:

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

$f(x)=\frac{1}{2}x^{2}-4x+5$

Convert to vertex form

$f(x)-5=\frac{1}{2}x^{2}-4x$

Factor the leading coefficient

$f(x)-5=\frac{1}{2}(x^{2}-8x)$

$f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x-4)^{2}$

$f(x)=\frac{1}{2}(x-4)^{2}-3$

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

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4 years ago

A ticket to the movies costs $7. you have $21. how many tickets can you buy?

Morgarella [4.7K]

You can buy 3 tickets

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3 years ago