Answer:
The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Explanation:
Given that,
Wavelength of red = 660 nm
Wavelength of blue = 470 nm
Separated d= 0.30 mm
Distance between screen and slits D= 5.0 m
We need to calculate the distance for red wavelength
Using formula for distance
Where, D = distance between screen and slits
d = separation of slits
Put the value into the formula
For blue wavelength,
Put the value into the formula again
We need to calculate the distance on the screen between the first-order bright fringes for each wavelength
Using formula for distance
Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Answer:
1.26m/s; 4.96m/s
Explanation
Acceleration is defined as the change I'm velocity of an object with respect to time.
Mathematically,
Acceleration (a) = change in velocity (v-u)/time (t)
Where v is the final velocity
u is the initial velocity
From the equation, it can be deduced that;
v = u+at
If the runner had an initial vertical velocity of -0.7 m/s over a period of 0.2seconds, its final velocity;
v = (-0.7)+9.81(0.2) (a=g=9.81m/s²)
v = -0.7+1.962
v = 1.26m/s
If the runner had an initial horizontal velocity of 3 m/s over a period of 0.2seconds, its final velocity;
v = 3+9.81(0.2)
v = 3+1.962
v = 4.96m/s
15 = a+(3-1)d
23 = a+(7-1)d
simultaneous eqs. solve for a and d
Answer:
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