All categories

3 years ago

The molecule that traps the sun's energy is ?.

Physics

1 answer:

kakasveta [241]3 years ago

7 0

The molecule that trap's the sun's energy is chlorophyll.

You might be interested in

A tornado lifts a truck 252 m above the ground ñ. As the storm continues, the tornado throws the truck horizontally. It lands 56

sashaice [31]

i think its 200 i hope that helps

8 0

3 years ago

Read 2 more answers

Describe the radioactive disintegration’s known as alpha, beta, and gamma decay

I am Lyosha [343]

What’s the question

5 0

3 years ago

A 2kg box is pushed along a flat frictionless surface with an applied force of 53.91newton j+19.62 j were j is horizontal and j

tamaranim1 [39]

Since the box doesn't move vertically at all, no work is done by the vertical component of the force.

If 53.91 Newtons is the horizontal component of the force (very unclear in the question), then the work done is

Work = (force) x (distance)

Work = (53.91 N) x (10 m)

Work = 539.1 Joules

Power = (work done) / (time to do the work)

Power = (539.1 joules) / (90 sec)

Power = (539.1/90) (joule/sec)

Power = 5.99 watts

=====================================

Note: If the mass of the box is only 2 kg, and you push it along the surface with a constant force of 53⁺ Newtons, and the surface really is frictionless, then that box is gonna cover a WHOOOOOLE LOT more than 10 meters in 90 seconds. I get 109,168 meters !

5 0

3 years ago

Two small conducting point charges, separated by 0.4 m, carry a total charge of 200 C. They repel one another with a force of 12

Lunna [17]

Answer:

200 C

Explanation:

Let C1 and C2 be their charges. According to Coulomb's law

$F_C = k\frac{C_1C_2}{R^2}$

where k = $8.99\times10^9 nm^2/C^2$ is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force

$120 = 8.99\times10^9\frac{C_1C_2}{0.4^2}$

$C_1C_2 = \frac{120*0.4^2}{8.99\times10^9} = 2.13\times10^{-9}$

Since their total charge is 200C:

$C_1 + C_2 = 200$ or $C_1 = 200 - C_2$

We can substitute the above equation

$C_1C_2 = (200 - C_2)C_2 = 2.13\times10^{-9}$

$-C_2^2 +200C_2 - 2.13\times10^{-9} = 0$

$C= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$C= \frac{-200\pm \sqrt{(200)^2 - 4*(-1)*(-0.00000000213)}}{2*(-1)}$

$C= \frac{-200\pm200}{-2}$

$C = 1.06 \times 10^{-11}$ or $C \approx 200$

So the larger charge is C = 200 C

8 0

3 years ago

Approximately what core temperature is required before hydrogen fusion can begin in a star?

valkas [14]

Answer:

The temperature required is near about 3 million kelvin

Explanation:

The brilliance of the star results from the nuclear reaction that take place in the core of the star and radiate a huge amount of thermal energy resulting from the fusion of hydrogen into helium.

For this reaction to take place, the temperature of the star's core must be near about 3 million kelvin.

The hydrogen atoms collide and starts and the energy from the collision results in the heating of the gas cloud. As the temperature comes to near about $1.5\times 10^{7 {\circ}C$ , the nuclear fusion reaction takes place in the core of the gas cloud.

The huge amount of thermal energy from the nuclear reaction gives the gas cloud a brilliance resulting in a protostar.

8 0

3 years ago