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zalisa [80]
2 years ago
9

Find the distance between the points (5,0) and (-5,3)

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
4 0

Answer:

10.4

Step-by-step explanation:

√(5--5)²+(0-3)²

√100+9

√109=10.4

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For the Christmas dance ,the dance committee needs three hours of music. Each song is an average of 3.5 minutes . how many song
GREYUIT [131]
An hour is 60 minutes

there are three hours so 
60*3=180

how many times will 3.5 go into 180 so 
180/3.5=51.43 or rounded up you get 52 songs (if they're good, they'll play 52 average songs and one half legnth songs)
so they will need 52 songs

3 0
3 years ago
Read 2 more answers
Which statements are appropriate to use in an online academic environment? Check all that apply.
Pavel [41]

Answer:

1,3, and 7th option.

Step-by-step explanation:

<em> I just did the questions.</em>

<em>Add me on instagram sheluvsayden</em>

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7 0
3 years ago
Can 927/100 be simplified
Genrish500 [490]
No, it cannot be simplified.  
Prime factors of 927:3*3*103
Prime factors of 100:2*2*5*5
No factors are in common, so this is the most simplified state.
3 0
4 years ago
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
3 years ago
Lol again another math solver help pls! LOL
gladu [14]

Answer:

b = 4

Step-by-step explanation:

5-1=5b-4b

4=b

4 0
3 years ago
Read 2 more answers
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