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zalisa [80]
2 years ago
9

Find the distance between the points (5,0) and (-5,3)

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
4 0

Answer:

10.4

Step-by-step explanation:

√(5--5)²+(0-3)²

√100+9

√109=10.4

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If you can please help thank you
zysi [14]

Answer:

d) 2x^2 + 2x -59

Step-by-step explanation:

(x-8)(x+4) + (x-3)(x+9) *multiply each term (...)(...)*

x^2 - 4x - 32 + x^2 + 6x -27 *combine like terms*

2x^2 +2x - 59

7 0
3 years ago
What is the slope of the line?
Yanka [14]

Answer:

m=\frac{4}{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (-2, 0)

Point (3, 4)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>.

  1. Substitute [SF]:                     m=\frac{4-0}{3+2}
  2. Subtract/Add:                       m=\frac{4}{5}
3 0
3 years ago
What is the range of the function below in set builder notation? y=|x-3|
Kisachek [45]

Answer:  \{y | \ y \in \mathbb{R}, \ y \ge 0\}

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

4 0
3 years ago
A surveyor standing at A notices two posts B and C on the opposite side of a canal. The posts are 120m apart. If the angle of si
AveGali [126]

Unfortunately there isn't enough information.

Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.

5 0
2 years ago
Write the points (-3,5) and (1,1) in slope-intercept form
Jobisdone [24]
Y=mx+b
m=slope
b=yint

find slope
slope between (x1,y1) and (x2,y2) is (y1-y2)/(x1-x2)

given
(-3,5) and (1,1)
slope=(5-1)/(-3-1)=4/-4=-1

y=-1x+b
find b
when x=1, then y=1
1=-1(1)+b
1=-1+b
add 1
2=b


y=-x+2
3 0
3 years ago
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