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Troyanec [42]
3 years ago
12

Explain why an increase in pressure will have NO EFFECT on the system at equilibrium: H2 + I2 ⇋ 2HI.

Chemistry
1 answer:
denpristay [2]3 years ago
3 0
2+2=4 and I am a pimp. No cap murdergang slat
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Convey the following information in the form of balanced chemical equation:
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Answer:

Carbon dioxide reacts with limewater (a solution of calcium hydroxide, Ca(OH) 2), to form a white precipitate (appears milky) of calcium carbonate, CaCO 3.

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QUESTION 1 The ____________________ fan switch is nothing more than a thermostat that closes on a rise in temperature to start t
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Write the formula for Zn+2 (SO4)-2
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4 0
3 years ago
Be sure to answer all parts.
Liula [17]

A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²

B. The cost of the patch to the nearest cent is 734 cents

<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>

We can convert 16.1 cm² to km² as illustrated below:

Conversion scale

1 cm² = 1×10⁻¹⁰ km²

Therefore,

16.1 cm² = 16.1 × 1×10⁻¹⁰

16.1 cm² = 1.61×10⁻⁹ km²

Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²

<h3>B. How to determine the cost in cent</h3>

We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:

1 cm² = 0.155 in²

Therefore,

16.1 cm² = 16.1 × 0.155

16.1 cm² = 2.4955 in²

Finally, we shall the determine the cost in centas fo r llow:

  • Cost per in² = $2.94 = 294 cent
  • Cost of 2.4955 in² =?

1 in² = 294 cent

Therefore,

2.4955 in² = 2.4955 × 294

2.4955 in² = 734 cents

Thus, the cost of the patch is 734 cents

Learn more about conversion:

brainly.com/question/2139943

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6 0
2 years ago
How do we measure the mass of an extrasolar planet?
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To determine a planet's mass, astronomers typically measure the minuscule movement of the star caused by the gravitational tug of an orbiting planet. For planets the massof Earth detecting such a tiny tug is extraordinarily challenging with current technology
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