Answer:
The answer is: <em>"Rarefactions"</em>
Explanation:
In a longitudinal wave, particles of the medium vibrate in a direction that is parallel to the direction that the wave travels. Places where particles of a medium crowd closer together are called compressions, and places where the particles spread farther apart are called rarefactions.
Answer:
b)4.46 L/hr
Explanation:
To solve this question we need to convert the mL to liters (Using the conversion of 1000mL = 1L) and convert the time from seconds to hours (3600s = 1hr)
<em>mL to L:</em>
1.24mL/s * (1L / 1000mL) = 0.00124L/s
<em>seconds to hours:</em>
0.00124L/s * (3600s / 1hr) = 4.46L/hr
Right answer is:
<h3>b)4.46 L/hr
</h3>
False. A group of cells is called a tissue.
Answer:
True
Explanation:
The oil drop experiment was carried out by Robert Millikan and Harvey Fletcher in 1909 to determine the charge of an electron. By balancing downward gravitation force with upward drag and electric force, they suspended small charged droplets of oil between two metal electrodes.
The charge over an oil droplet was often an integral value of e, was determined by changing the intensity of the electric field.
So, the given statement is true
Answer:
1.510 × 10⁻¹³ g
Explanation:
Step 1: Given data
Number of atoms of vanadium: 1.000 × 10⁹ atoms
Step 2: Calculate the molecules of V₂O₅ that contain 1.000 × 10⁹ atoms of V
Each molecule of V₂O₅ has 2 atoms of V.
1.000 × 10⁹ atom V × (1 molecule V₂O₅/2 atom V) = 0.5000 × 10⁹ molecule V₂O₅
Step 3: Calculate the moles corresponding to 0.5000 × 10⁹ molecules of V₂O₅
We will use Avogadro's number: there are 6.022 × 10²³ molecules of V₂O₅ in 1 mole of V₂O₅.
0.5000 × 10⁹ molecule × (1 mol/6.022 × 10²³ molecule) = 8.303 × 10⁻¹⁶ mol
Step 4: Calculate the mass corresponding to 8.303 × 10⁻¹⁶ moles of V₂O₅
The molar mass of V₂O₅ is 181.88 g/mol.
8.303 × 10⁻¹⁶ mol × 181.88 g/mol = 1.510 × 10⁻¹³ g
