Um comerciante comprou um lote de cabos e quer colocá-los à venda em pedaços, o maior possível, com o mesmo comprimento e sem ha ver perdas. Sabendo que, os cabos têm comprimento de 96m, 60m e 84m, qual a medida dos pedaços a serem oferecidos aos clientes?
1 answer:
Answer:
12
Step-by-step explanation:
The computation of the size of the customers is shown below:
Here we find the greatest common divisor of the given numbers
96, 60, 84 ÷ 2
48, 30, 42 ÷ 2
24, 15, 21 ÷ 2
12, 15, 21 ÷ 2
6, 15, 21 ÷ 2
3, 15, 21 ÷ 3
1, 5, 7 ÷ 5
1, 1, 7 ÷ 7
1, 1, 1
By this there are three numbers i.e. 2, 2 and 3
So, the lease common denominator is
= 2 × 2 × 3
= 12
You might be interested in
Answer:
3+3tt=total amount of snow
Step-by-step explanation:
y=mx+b is used to show increase
In this case, b is the original 3 inches of snow. m is the constant growth, and x is tt, or the amount of time it is being compared to. y is the total.
Answer:
Y=(x+4)*2-3
=x*2+8x+16-3
=x*2+8x+13
So the standard form is B
Answer:
Common ratio r = 2
Step-by-step explanation:
Hence, common ratio is 2.
Answer:
C
Step-by-step explanation:
The rest are based on time or based on money. (Which you don't know the rate of how often they buy.) I would chose C, if I'm wrong sorry.
Answer:
Marcus needs to buy at least twice as many pounds of apples as pounds of bananas
