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pogonyaev
2 years ago
7

Um comerciante comprou um lote de cabos e quer colocá-los à venda em pedaços, o maior possível, com o mesmo comprimento e sem ha

ver perdas. Sabendo que, os cabos têm comprimento de 96m, 60m e 84m, qual a medida dos pedaços a serem oferecidos aos clientes?
Mathematics
1 answer:
Aleks [24]2 years ago
6 0

Answer:

12

Step-by-step explanation:

The computation of the size of the customers is shown below:

Here we find the greatest common divisor of the given numbers

96, 60, 84 ÷ 2

48, 30, 42  ÷ 2

24, 15, 21 ÷ 2

12, 15, 21 ÷ 2

6, 15, 21 ÷ 2

3, 15, 21  ÷ 3

1, 5, 7 ÷ 5

1, 1, 7 ÷ 7

1, 1, 1

By this there are three numbers i.e. 2, 2 and 3

So, the lease common denominator is

= 2 × 2 × 3

= 12

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What is the surface area of the rectangular prism below?
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Answer:

B ( 432 units^2)

Step-by-step explanation:

Total surface area= 2*(6*6)+ 4*(15*6)

There are 2 squares at each end of the same size so total area will be 2*(6*6)

If we look at the rectangles( bottom, top and the sides), we can see that all are of same dimensions and there are 4 of them so it's 4*(15*6)

In short, total surface area= 2*(6*6)+ 4*(15*6) = 432 units^2

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2 years ago
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