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3 years ago

Please help please!!!!!

Mathematics

1 answer:

LenKa [72]3 years ago

7 0

Top and bottom are $\pi each$

curved surface is 2*9* $\pi$

so in total, its 18+2=20 $\pi$ thats your answer

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Solve x/4 > 2 ............... Thank you :)

VikaD [51]

x/4 > 2

Simplify by multiplying 4 on both sides

x>8

Which is,

<h2>THE SECOND OPTION</h2>

-Hunter

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2 years ago

The amount of time it takes Heather to cook dinner is directly proportional to the number of ingredients involved. If it takes h

Lemur [1.5K]

15 minutes!

Since the ratio is 1 : 1, for every one ingredient it will take her one minute. 15 ingredients = 15 minutes.

Hope that helped!

:D®

P.S. I wonder what she's cooking.

6 0

3 years ago

Read 2 more answers

How do u graph this

iren [92.7K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\$

$\bf \bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

so hmmm $\bf \begin{array}{llcll}
f(x)=&0.5sin(x)&+2\\
&\uparrow &\uparrow \\
&A&D
\end{array}$

instead of going up/down by 1unit, it goes up/down by half
and then it's shifted upwards by 2, so the midline will end up at y = 2

but basically the same sin(x) graph, just a bit shorter due to the smaller amplitude.

5 0

3 years ago

The median of an isosceles triangle is the same segment in the triangle as the _______.

hoa [83]

Answer: Altitude!!!

Step-by-step explanation:

APEX

5 0

3 years ago

Pls pls help me I will mark you brainest

Ann [662]

Answer:

130

Step-by-step explanation:

10+10+5+5=30

50+50=100

30+100=130

5 0

3 years ago