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Radda [10]
3 years ago
8

The figure below shows regions of the electromagnetic

Physics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

The electromagnetic spectrum in order of increasing frequency is - radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.

The frequency of the gamma rays is >3×10

19

m.

Hence, the gamma rays has the maximum frequency in the electromagnetic spectrum.

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I need help with this question. Anyone?
cluponka [151]
The closest answer i would go with is b, I'm not completely sure because I'm not sure what the question actually means because there could be any meaning 
5 0
3 years ago
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What is the free-fall acceleration at the surface of the jupiter?
Rufina [12.5K]

Answer:

24.79 m/s2

Explanation:

Let us assume that there is an object with a mass of 'm' on the

 

Jupiter. Jupiter will attract this object:

mg_j=G\frac{mM_j}{r_j^{2} }

g_j=G\frac{M_j}{r_j^{2} }

g_j=6.67*10^{-11} \frac{1.9*10^{27} }{71492000^{2} }

g_j=24.79m/s^{2}

4 0
3 years ago
A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s afte
lana66690 [7]

Answer: The ball's acceleration is 2.35 m/s2

Explanation: Please see the attachment below

6 0
3 years ago
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A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same direction. What is the largest distance the stu
stepan [7]

Answer:

7.1 m

Explanation:

Given:

Distance traveled by the student in the first attempt = (2.9 \pm 0.1)\ m

Distance traveled by the student in the second attempt = (3.9 \pm 0.2)\ m

So, the maximum distance that the student could travel in this attempt = (2.9+0.1)\ m = 3.0\ m

So, the maximum distance that the student could travel in this attempt = (3.9+0.2)\ m = 4.1\ m

Since the student first moves straight in a particular direction, rests for a while and then moves some distance in the same direction.

So, the largest distance that the student could possibly be from the starting point would be the largest distance of the final position of the student from the starting point.

And this distance is equal to the sum of the maximum distance possible in the first attempt and the second attempt of walking which is 7.1 m.

Hence, the largest distance that the student could possibly be from the starting point is 7.1 m.

5 0
3 years ago
An insulated lamp bulb is on the bottom of a swimming pool at a point 2.5 m from a wall; the pool is 2.5 m deep and filled to th
pashok25 [27]

Answer:

option A

Explanation:

given,

lamp position from pool wall = 2.5 m

height of the pool = 2.5 m

now,

tan \theta = \dfrac{P}{B}

\theta =tan^{-1}(\dfrac{2.5}{2.5})

\theta =45^0

from the triangle

θ = i = 45°

using Snell's law

n₁ sin i = n₂ sin r

n₁ =4/3     n₂ = 1  

now,

\dfrac{sin r}{sin i}=\dfrac{n_1}{n_2}

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sin r=\dfrac{1}{\sqrt{2}}\times \dfrac{4}{3}

r = sin⁻¹(0.9428)

r = 70.5°

hence, the correct answer is option A

8 0
3 years ago
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