Answer:
33 N
Explanation:
v = Velocity of fluid = 8+2 = 10 m/s
= Density of fluid = 1.2 kg/m³
C = Coefficient of drag = 1.1
A = Cross sectional area = 0.5 m²
Drag force is given by

The drag force on the athlete is 33 N
The answer to the question would be jet streams.
Answer: A. 2.0m above ground
Explanation:
Height of the pitcher from the floor of his mound = 1.8m
Height of the mound above the rest of the field = 0.2m
Since the height difference between the mound and the ground the catcher stands on = 0.2m and the pitcher throws the ball horizontally, then the catcher has to hold his glove at (1.8 + 0.2)m
above ground.
= 2.0m above ground (option A)
if in 1 second the jet goes 428 meters and you want to know how long it takes to go 237 meters you just divide 237/428
it can be written like this
_1_ = __x__
428 237
cross multiply
428 times x = 1 times 237
428x=237
divide by 428 on both sides
x= 237/428
x=0.5537 seconds
Answer:
Soup kitchen, on site, and 2 last ones
Explanation: