2 years ago

HELP ME PLEASE!!!

Mathematics

1 answer:

snow_tiger [21]2 years ago

4 0

Answer:

(4,-2)

(2,-2)

(0,0)

Please let me know if I was right and good luck

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antiseptic1488 [7]

Answer:

I believe it would be 4x-8=-3x+13

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2 years ago

3(x + y + h)=<br> Can someone help me with this

Nastasia [14]

Answer:

3x +3y +3h

that’s the farthest you can solve since you don’t know the variable’s values

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2 years ago

<img src="https://tex.z-dn.net/?f=48-%2B20" id="TexFormula1" title="48-+20" alt="48-+20" align="absmiddle" class="latex-formula"

poizon [28]

Answer:

240

the always the + and the - = +

so positive plus minus equals positive

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2 years ago

Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con

monitta

Let $f(x)=e^{-1/x}$ . Then $f'(x)=\frac1{x^2}e^{-1/x}>0$ for all $x\ge2$ , so $f$ is strictly increasing. As $x\to\infty$ , $e^{-1/x}\to e^0=1$ , so $f$ is bounded above by 1. This is to say,

$e^{-1/x}$

and the integral of $\frac1{x^2}$ converges over the same domain, so this integral must also converge by comparison.

We have, by setting $y=-\frac1x$ ,

$\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}$

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2 years ago

Which are points drawn in this figure?

professor190 [17]

S, r, c and m

hope this helps :)

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3 years ago

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