The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
You have to use your standard normal table (or calculator) for these. The area under the curve should be 1, a z-value corresponds to the probability and is area to the left of that z.
a. A simple reverse lookup of 0.9750. z=1.96
b. Total area up to z would be 0.5+0.4750, so reverse look up 0.9750 and find z=1.96
c. A simple reverse lookup. z=0.61
d. Area to the left of z would b 1-0.1314, so lookup 0.8686 and find z=1.12
e. A simple reverse lookup. z=0.44
f. Just invert the area: 1-0.33 = 0.67 and reverse lookup: z=0.44
Answer:
40 cubes or cubic inches or whatever measurement the problem is using
15, 1 ground beef cost $5
The required value is 0.286 and 
Step-by-step explanation:
Since we have given that
Number of students = 7
Number of students are from Middle Georgia State College = 4
So, Probability that both of the interviewed students are from Middle Georgia State College is given by
Hence, the required value is 0.286 and
