The ratio of building heights will be the same as the ratio of shadow lengths.
(taller building)/(shorter building) = (longer shadow)/(shorter shadow)
(taller building)/(84 ft) = (110 ft)/(46 ft) . . . . . . fill in the given numbers
(taller building) = (84 ft)*(110/46) ≈ 200.9 ft . . multiply by 84 ft, evaluate
The appropriate selection is
D) 200.9 ft
Answer:
The patient would receive 1.05mg of the drug weekly.
Step-by-step explanation:
First step: How many mcg of the drug would the patient receive daily?
The problem states that he takes three doses of 50-mcg a day. So
1 dose - 50mcg
3 doses - x mcg
x = 50*3
x = 150 mcg.
He takes 150mcg of the drug a day.
Second step: How many mcg of the drug would the patient receive weekly?
A week has 7 days. He takes 150mcg of the drug a day. So:
1 day - 150mcg
7 days - x mcg
x = 150*7
x = 1050mcg
He takes 1050mcg of the drug a week.
Final step: Conversion of 1050 mcg to mg
Each mg has 1000 mcg. How many mg are there in 1050 mcg? So
1mg - 1000 mcg
xmg - 1050mcg
1000x = 1050

x = 1.05mg
The patient would receive 1.05mg of the drug weekly.
We can write the function in terms of y rather than h(x)
so that:
y = 3 (5)^x
A. The rate of change is simply calculated as:
r = (y2 – y1) / (x2 – x1) where r stands for rate
Section A:
rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)
rA = 12
Section B:
rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)
rB = 300
B. We take the ratio of rB / rA:
rB/rA = 300 / 12
rB/rA = 25
So we see that the rate of change of section B is 25
times greater than A
Answer:
5.93 years
Step-by-step explanation:
The continuous compounding formula tells you the amount after t years will be ...
A = Pe^(rt) . . . . principal P compounded continuously at annual rate r for t years
7400 = 5500e^(0.05t)
ln(7400/5500) = 0.05t . . . . divide by 5500, take natural logs
t = 20×ln(74/55) ≈ 5.93
It will take about 5.93 years for $5500 to grow to $7400.
Right Triangles and the Pythagorean Theorem
The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2 , can be used to find the length of any side of a right triangle.
The side opposite the right angle is called the hypotenuse (side c in the figure).