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eimsori [14]
3 years ago
14

Jenna was 4 4/6 feet tall last year. This year she is 5 2/6 feet tall. How many feet did Jenna grow in the past year

Mathematics
2 answers:
kompoz [17]3 years ago
8 0
You could turn the mixed fractions into improper fractions so 4 4/6 would become 28/6 and 5 2/6 would become 32/6. Then you can subtract 32/6 by 28/6 which would be 4/6 simplified into 2/3
oee [108]3 years ago
5 0
You want to subtract the heights. 5 2/6-4 4/6=5 1/3-4 2/3=2/3.
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What is the 50th term of the arithmetic sequence having u(subscript)1 = -2 and d = 5
OLga [1]

Answer:

243

Step-by-step explanation:

The general term for this arithmetic sequence is:

a(n) = -2 + 5(n - 1).

Then a(50) = -2 + 5(49) =   243

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2 years ago
Use the image above to write a conjecture about regular polygons and lines of symmetry
Tatiana [17]
To find conjecture about regular polygon, use the formula \frac{360}{n}

Where, n = number of sides of the regular polygone

1) Triangle
n =3
So, Conjecture of the triangle = \frac{360}{3} = 120

2) Square
n =4
So, Conjecture of the square = \frac{360}{4} = 90

3) Pentagone
n = 5
So, Conjecture of the pentagon = \frac{360}{5} = 72

4) Hexagone
n = 6
So, Conjecture of the pentagon = \frac{360}{6} = 60.
7 0
3 years ago
Read 2 more answers
PLEASE HELP!
hram777 [196]

Answer:

<em>Triangle ABC is like a reflection to triangle AYZ.  They are the same size and line AB are the same as line YA</em>

Step-by-step explanation:

5 0
2 years ago
Which inequality models this situation?
lora16 [44]
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The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.10
Salsk061 [2.6K]

For the bell-shaped graph of the normal distribution of weights of Hershey kisses, the area under the curve is 1, the value of the median and mode both is 4.5338 G and the value of variance is 0.0108.

In the given question,

The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.1039 G.

We have to find the answer of many question we solve the question one by one.

From the question;

Mean(μ) = 4.5338 G

Standard Deviation(σ) = 0.1039 G

(a) We have to find for the bell-shaped graph of the normal distribution of weights of Hershey kisses what is the area under the curve.

As we know that when the mean is 0 and a standard deviation is 1 then it is known as normal distribution.

So area under the bell shaped curve will be

\int\limits^{\infty}_{-\infty} {f(x)} \, dx= 1

This shows that that the total area of under the curve.

(b) We have to find the median.

In the normal distribution mean, median both are same. So the value of median equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of median is also 4.5338 G.

(c) We have to find the mode.

In the normal distribution mean, mode both are same. So the value of mode equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of mode is also 4.5338 G.

(d) we have to find the value of variance.

The value of variance is equal to the square of standard deviation.

So Variance = (0.1039)^2

Variance = 0.0108

Hence, the value of variance is 0.0108.

To learn more about normally distribution link is here

brainly.com/question/15103234

#SPJ1

3 0
10 months ago
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