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stira [4]
3 years ago
13

Subtract 8 from me. Then add 21. If you divide me by 4 and add 21 you get 29. What number am I?

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

19

Step-by-step explanation:

x - 8 + 21 ÷ 4 + 21 = 29

x - 8 + 21 ÷ 4 = 29 - 21

                     = 8

x - 8 + 21 = 8 x 4

              = 32

x - 8 = 32 - 21

       = 11

x = 11 + 8

  = 19

Therefore the number is 19. A bit confusing to me at first but I solved it :)

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\bold{Heya!}

Your answer to this is:

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<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u />\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)

\sf{Apply \: rule:} \: (a) = a

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\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1

\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}

\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

Hopefully This Helps ! ~

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\underline{Answer :}

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